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3 years ago

The state of matter of the interior of the sun and other stars

2 answers:

7 0

Answer: It is, as all stars are, a hot ball of gas made up mostly of Hydrogen. The Sun is so hot that most of the gas is actually plasma, the fourth state of matter. ... As we heat up liquid, the liquid turns to gas. Gas is the third state of matter

Explanation:

Harman [31]3 years ago

6 0

Answer:

Plasma, which is the fourth state of matter

Explanation:

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An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam

MAXImum [283]

Explanation:

The given data is as follows.

Mass of mixture = 0.3471 g

As the mixture contains oxalic acid and benzoic acid. So, oxalic acid will have two protons and benzoic acid has one proton.

This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

Hence, moles of NaOH in 97 ml = $\frac{0.1090 \times 97}{1000}$

= $10.573 \times 10^{-3} mol$

Moles of HCl in 21.00 ml = $\frac{0.2060 \times 21}{1000}$

= $4.326 \times 10^{-3}$ mol

Therefore, total moles of NaOH that reacted are as follows.

$10.573 \times 10^{-3} mol$ - $4.326 \times 10^{-3} mol$

= $6.247 \times 10^{-3}$ mol

So, total 3 mole of NaOH will react with 1 mole of mixture. Therefore, number of moles of NaOH reacted with benzoic acid is as follows.

$\frac{6.247 \times 10^{-3}}{3}$

= $2.082 \times 10^{-3}$ mol

Since, molar mass of NaOH is 40 g/mol. Therefore, calculate the mass of NaOH as follows.

$2.082 \times 10^{-3} mol \times 40 g/mol$

= $83.293 \times 10^{-3}$ g

= 0.0832 g

Whereas molar mass of benzoic acid is 122 g/mol.

Therefore, 40 g NaOH = 122 g benzoic acid

So, 0.0832 g NaOH = $\frac{122 g}{40 g} \times 0.0832 g$

= 0.253 g

Hence, calculate the % mass of benzoic acid as follows.

$\frac{0.253 g}{0.3471 g} \times 100$

= 73.10%

Thus, we can conclude that mass % of benzoic acid is 73.10%.

4 0

3 years ago

Which of the following statements is a true statement regarding a solution with [H1+] =1x10-5 M and [OH1-]= 1x10-9 M?

zheka24 [161]

Answer:

B. The [H1+] >[OH1-] and the solution is acidic

4 0

3 years ago

I Need help with this worksheet I Need the Work Please Thank you

Komok [63]

1. a. 3

b. 2

2. a. 4

b. 6

3. a. 1

b. 2

4. a. 5

4 0

2 years ago

For each of the following cases, identify the order with respect to the reactant, A. Case (A ----> product)

damaskus [11]

Answer:

The answers to the question are

1. 2nd and above order order

2. 2nd order

3. 1/2 order

4. 1st order

5. 0 order

Explanation:

We have $\frac{N}{N_{0} } = e^{-\lambda t}$

1. For nth order reaction half life $t_{\frac{1}{2} }$ ∝ $\frac{1}{[A_{0} ]^{n-1} }$

Therefore for a 0 order reaction increasing concentration of the reactant there will increase $t_{\frac{1}{2} }$

First order reaction is independent [A₀].

Second order reaction [A₀] decrease, increase.

Similarly for a third order reaction

1. 2nd order

2. 2nd order reaction

3. Order of reaction is 1/2.

4. 1st order reaction.

5. Zero order reaction.

5 0

3 years ago

What is the maximum number of moles of Al2O3 that can be produced by the reaction of .4 mol of Al with .4 mol of O2

Darya [45]

Given:

Moles of Al = 0.4

Moles of O2 = 0.4

To determine:

Moles of Al2O3 produced

Explanation:

4Al + 3O2 → 2Al2O3

Based on the reaction stoichiometry:

4 moles of Al produces 2 moles of Al2O3

Therefore, 0.4 moles of Al will produce:

0.4 moles Al * 2 moles Al2O3/4 moles Al = 0.2 moles Al2O3

Similarly;

3 moles O2 produces 2 moles Al2O3

0.4 moles of O2 will yield: 0.4 *2/3 = 0.267 moles

Thus Al will be the limiting reactant.

Ans: Maximum moles of Al2O3 = 0.2 moles

4 0

3 years ago

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The state of matter of the interior of the sun and other stars​

The state of matter of the interior of the sun and other stars