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3 years ago

Given no other restrictions, what are the domain and range of the following function?

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

6 0

Answer: I'm pretty sure the correct answer is C.

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Lorenzo is planning a 285-mile trip. His car’s EPA rating is 18 mpg. The number of gallons of gas that Lorenzo will need for the

SpyIntel [72]

It would require 15.8333333 to make that trip.

4 0

3 years ago

Read 2 more answers

A map of New York has a scale of 1/2 inch : 5 miles. Cindy knows the

saveliy_v [14]

Answer:

8.5 inches

Step-by-step explanation:

1/2 in = 5 miles

? = 85 miles.

So you would do 85/5 to figure out how many times you have to multiply 5 to get to 85.

85/5= 17

So then you would multiply 17 by 1/2 to get the answer 8.5. So that would b 8.5 inches

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3 years ago

A above ground garden is rectangular and has a length of 15 feet and a height of 2 feet. It will hold 375 cubic feet of soil. Wh

Fittoniya [83]

Answer: $12.5\ ft$

Step-by-step explanation:

Given

Length L=15 feet

width b=2 feet

Volume V=375 cubic feet

Suppose h is the height

Volume is given by $V=l\times b\times h$

$\Rightarrow 375=15\times 2\times h\\\Rightarrow h=\frac{375}{30}=12.5\ ft$

4 0

3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

3 years ago

Is the given number a solution of the equation?<br> 8=2+3; 10

kykrilka [37]

Answer:

No.

Step-by-step explanation:

8 doesn't equal 0 on the very right, which means it's not a solution to the equation. So therefore, it is false based on the equation.

7 0

3 years ago