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Sidana [21]
3 years ago
7

Graph this inequality: x < -7

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

<------------o

-------------------------------------------------

               |               |

              -7             0

Step-by-step explanation:

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A variable needs to be eliminated to solve the system of equations below. Choose the
notsponge [240]

Answer:

x=-2

y= 8

Step-by-step explanation:

Given data

10x – 2y = -36-----------1

7x – 2y = -30--------------2

-Subtract to eliminate y

3x-0= -6

3x= -6

x= -6/3

x= -2

Put x= -2 in

7(-2)– 2y = -30

-14-2y=-30

-14+30=2y

16=2y

y= 16/2

y= 8

8 0
3 years ago
Find the solution set to this inequality:
marusya05 [52]

Answer:

vruu

Step-by-step explanation:

skvnrwniohwrigjqepvpoqepmveppiehpihuorhg8hginvknkcmksmlkqslqbyftdrses6duguhojcfxzwexyvyih8ttde5setvjmpokuigcfxdetguinjnh fxtrfyhbh c

\int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx x^{2} \frac{x}{y} \pi \int\limits^a_b {x} \, dx \sqrt{x} \frac{x}{y} \frac{x}{y} x^{2} x^{2}

7 0
3 years ago
Need help asap to find what the m and n equal to.
Mariana [72]

Answer:

Are there any answers

Step-by-step explanation:

8 0
3 years ago
If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components a
sammy [17]
There is some inforrmation that is missing in this question. It should read:

<span><span>A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

</span><u>Answers</u>
<span>Part 1.   0.02
Part 2.  </span></span>0.0375<span><span>

</span><u>Explanation</u>
The probability is a chance of an event happening. It is calculated as;
probability = (Number of favourable outcome)/(Number of available outcome)

Part 1
6 are chosen at random. If 4 are not defective, then 2 are defective.
P(at least 4 are not defective) = 4/40 </span>× 2/10
                                                = 1/10 ×1/5
                                                = 1/50
                                                 = 0.02

Part 2
8 are chosen at random. If 3 are defective, the 5 are not defective. 
P(3 are defective) = 3/40 × 5/10 
                             = 15/400
                             = 3/80
                            = 0.0375
4 0
3 years ago
Which of the following is an example of a quadratic equation?
jasenka [17]

Answer:

C) any eqaution that has a variable or number squared is a qaudratic equation

5 0
3 years ago
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