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Lunna [17]
2 years ago
16

Which function is negative for the interval [–1, 1]? On a coordinate plane, a curved line with a minimum value of (negative 1, n

egative 2), crosses the x-axis at (negative 2.5, 0) and (0.5, 0), and the y-axis at (0, negative 1). On a coordinate plane, a curved line with a minimum value of (0, negative 2), crosses the x-axis at (negative 1.5, 0) and (1.5, 0). On a coordinate plane, a curved line with a maximum value of (0, 2) and a minimum value of (1.5, negative 2.75), crosses the x-axis at (negative 0.6, 0) and (0.6, 0). On a coordinate plane, a curved line with a maximum value of (negative 1.25, 4) and a minimum value of (1.5, negative 3.5), crosses the x-axis at (negative 1.75, 0), (0.75, 0), and (1.75, 0), and crosses the y-axis at (0, 2).
Mathematics
2 answers:
timofeeve [1]2 years ago
9 0

Answer:it’s b on edg

Step-by-step explanation:

Doss [256]2 years ago
7 0

Answer:

A. On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2.5, 0) and (0.5, 0), and the y-axis at (0, negative 1).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

A. On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2.5, 0) and (0.5, 0), and the y-axis at (0, negative 1).

B. On a coordinate plane, a curved line with a minimum value of (0, negative 2), crosses the x-axis at (negative 1.5, 0) and (1.5, 0).

C.  On a coordinate plane, a curved line with a maximum value of (0, 2) and a minimum value of (1.5, negative 2.75), crosses the x-axis at (negative 0.6, 0) and (0.6, 0).

D. On a coordinate plane, a curved line with a maximum value of (negative 1.25, 4) and a minimum value of (1.5, negative 3.5), crosses the x-axis at (negative 1.75, 0), (0.75, 0), and (1.75, 0), and crosses the y-axis at (0, 2).

Apologies if I am wrong, I am not great with graphs but I hoped I helped.

<3 Enjoy,

    Dea

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Travelling at a
Degger [83]

Answer:

2:25

Step-by-step explanation:

Time=distance/speed

81/36=2.25

2:25 is the time for how long this will take!

3 0
2 years ago
The prime factorization of 132=2*2*3*11<br><br> a.what is the prime factorization of 88?
Harrizon [31]
The prime factorization of 88 is 11 x 2 x 2 x 2 the only factor of 88 that prime numbers are 2 and 11
8 0
3 years ago
Laura wrote and solved the following expression to find the total number of beads Lina has if there are 6 beads in each packet.
bulgar [2K]
<h3>The number of beads lina has is 31</h3><h3>Laura made a mistake by adding the constant 7 and variable 4b</h3>

<em><u>Solution:</u></em>

Given that,

Laura wrote and solved the following expression to find the total number of beads Lina has

There are 6 beads in each packet

7+4b = 11b

= 11(6)

=66

From given,

Lina has a total of 7 + 4b beads

Given that, There are 6 beads in each packet

Substitute b = 6

7 + 4(6)

Simplify

7 + 24

Add

31

Thus, she has a total of 31 beads and not 66 beads

Laura made a mistake by adding the constant 7 and variable 4b

But a constant and variable cannot be added

4 0
3 years ago
Find the slop from the given equation. 2x + 4y + 7 = 0
antiseptic1488 [7]

The slope of the line would be -1/2.

To find the slope we need to make the line in the form y = mx + b:

2x + 4y + 7 = 0

2x + 4y = -7

4y = -2x - 7

÷ 4

y = (-2/4)x - (7/4)

-2/4 simplifies to -1/2.

I hope this helps!


6 0
3 years ago
1140 was rounded to the nearest ten.<br>What is the upper bound?<br>​
zloy xaker [14]

Answer:

1145

Step-by-step explanation:

  • <em>The upper bound is the smallest value that would round up to the next estimated value</em>.

Since the number was rounded to nearest ten, the upper bound is:

  • 1145

which rounds up to 1150 which is the next estimated value greater than 1140

8 0
3 years ago
Read 2 more answers
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