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Naddika [18.5K]
3 years ago
11

if the density of water is 1 g/ml, what would happen to an object with a mass of 80 g and a volume of 100 cubic cm when you plac

e it in water
Chemistry
1 answer:
Nastasia [14]3 years ago
5 0

Answer:

<em>that</em><em> </em><em>obj</em><em>ect</em><em> </em><em>will</em><em> </em><em>float</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>water</em>

Explanation:

Since the density of water is greater than that of the object , the object will float on the water.

NB. Density of the object=

\frac{mass}{volume}

Given that mass of the object is 80g and volume 100cm^3

substituting them in the formula

Density=80g/100cm^3

Density=0.8g/cm^3

<em>sin</em><em>ce</em><em> </em><em>0</em><em>.</em><em>8</em><em><</em><em>1</em><em> </em><em>whi</em><em>ch</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>dens</em><em>ity</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>obj</em><em>ect</em><em> </em><em>and</em><em> </em><em>water</em><em> </em><em>respect</em><em>ively</em><em>,</em><em> </em><em>the </em><em>obj</em><em>ect</em><em> </em><em>will</em><em> </em><em>float</em><em>.</em>

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3 years ago
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Answer:

The coefficient for PH3 is 8. Option D is correct.

Explanation:

Step 1: The unbalanced equation

P2H4(g) ⇆ PH3(g) + P4(s)

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4 years ago
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Answer:

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Explanation:

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3 years ago
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The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>

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<span>1 mole of NH3 = 17 g </span>
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Answer is: 5,9.
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