All categories

3 years ago

Select 2-possible ointment bases. Select one or more:

Chemistry

1 answer:

fredd [130]3 years ago

7 0

Answer:

The correct option is: c. petroleum jelly, d. Polyethylene glycol 4000/600 mixture

Explanation:

Topical medications are used for the treatment of ailments and include ointments, gels, lotions creams etc. that can applied directly on the surface of the body i.e. skin.

An ointment base medication gets rapidly absorbed into the skin. Some of the examples of ointment bases include water-soluble bases: polyethylene glycol, hydrocarbon bases: petroleum jelly, paraffin wax.

You might be interested in

Acetic acid weighs 60g contains 40% carbon, 6.67% hydrogen, and 55.33% oxygen. Calculate it’s molecular formula.

nignag [31]

C₂H₄O₂ is the molecular formula of acetic acid

Explanation:

Acetic acid have a molecular wight of 60 g/mol.

The correct mass percentages for acetic acid are 40% carbon, 6.67% hydrogen and 53.33 % oxygen.

To find the molecular formula knowing the elements mass percentages we use the following algorithm:

we divide each percentage by the atomic weight of the element

for carbon 40 / 12 = 3.33

for hydrogen 6.67 / 1 = 6.67

for oxygen 53.33 / 16 = 3.33

now we divide each value obtained by the smallest value, which is 3.33

for carbon 3.33 / 3.33 = 1

for hydrogen 6.67 / 3.33= 2

for oxygen 3.33 / 3.33 = 1

empirical formula for acetic acid is CH₂O

molecular formula for acetic acid is (CH₂O)ₓ

30x g/mol = 60 g/mol (given by the problem)

x = 2

so the molecular formula for acetic acid is C₂H₄O₂

Learn more about:

molecular formula

brainly.com/question/11161266

brainly.com/question/1247523\

#learnwithBrainly

6 0

3 years ago

Can a solid defuse into both a liquid and a solid

MariettaO [177]

Diffusion of one state of matter into another: Solid can diffuse in liquid. When sugar is added to water, whole water becomes sweet without stirring it because of diffusion of sugar into water. ... Carbon dioxide and oxygen are the two gases in air which dissolves in water by diffusion.

5 0

2 years ago

Read 2 more answers

which are correct formulas for ionic compounds? for those that are not correct, give the correct formula and justify your answer

galina1969 [7]

Answer:

a. AlCl is incorrect because Al has a +3 charge while Cl only has a -1 charge. The correct formula would be AlCl₃. This balances the charges.

b. Na₃SO₄ is incorrect because Na has a charge of +1 and there are three of them so its +3 and SO₄ has a charge of -2. The correct formula would be Na₂SO₄. This balances the charges.

c. BaOH₂ is incorrect because the polyatomic ion OH would not be written that way. It would be written like this Ba(OH)₂. Writing it like BaOH₂ gives the impression that instead of having 2 OH it has 2 H and 1 O.

d. Fe₂O is incorrect because Fe either has a +2 charge or +3 charge while O has a -2 charge. Possible correct answers could be FeO (iron (II) oxide) or Fe₂O₃ (iron (III) oxide).

4 0

3 years ago

3.Firefighters’ uniform is coated with a plastic that is fire resistant. Identify the plastic from the given

Tresset [83]

Answer: b. Melamine

Explanation:

5 0

3 years ago

(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 12g Zinc Solid + 24g Silver Nitrate

VARVARA [1.3K]

Answer:

Zn + 2AgNO₃ → Zn(NO₃)₂ +2Ag

13.34g Zn(NO₃)₃ and 15.24g Ag are formed if reaction is 100% complete.

Explanation:

molar mass of Zn=65 g

molar mass of AgNO₃=170 g

molar mass of Zn(NO₃)₂ =189 g

molar mass of Silver = 108 g

Zn + 2 AgNO₃ → Zn(NO₃)₂ +2 Ag eq(1)

1 mole Zn reacts with 2 moles Silver nitrate to give 1 mole Zinc nitrate and 2 moles Silver

65 g Zn reacts with 2×170 g of AgNO₃ → 189 g Zn(NO₃)₂ and 2×108 g Ag - eq(2)

First find limiting reagent of the reaction

65g Zn reacts with 2×170g of AgNO₃

12 g Zn reacts with (12÷65)×2×170 g AgNO₃

=62.7 g AgNO₃

For the reaction to go to 100% yield 12 g Zn will need 62.7 g AgNO₃

but amount of AgNO₃ is 24 g

So the reaction yields is limited by amount of AgNO₃.

AgNO₃ is the limiting reagent.

So calculate the yield of products with the amount of AgNO₃

by eq(2)

2× 170 gAgNO₃ gives 189 g Zn(NO₃)₃

=340 g AgNO₃ gives 189 g Zn(NO₃)₃

24 g AgNO₃ gives (24÷340) ×189 g Zn(NO₃)₃

=13.34g Zn(NO₃)₃

again by eq2

2×170 g AgNO₃ gives 2×108 g Ag

= 340 g AgNO₃ gives 216 g Ag

24 g AgNO₃ gives (24÷340)×216 g Ag

= 15.24g Ag

6 0

3 years ago