Answer:
10 atm
Explanation:
There's a lot to do here, but lets take it one step at a time. First, let's write a balanced equation for the decomposition of potassium chlorate into potassium chloride and oxgyen gas.
2 KClO3 → 2 KCl + 3 O2
Now let's find the moles of the KClO3 (molar mass 122.55 g/mol) that we have take 10 g/122.55 g/mol, grams will cancel and we are left with 0.0816 moles. lets divide that by two since we have a two in front of the KClO3 in the equation, and then multiply that number by 5 since it's the total moles of products, in summary, multiply by 5/2 to get 0.204 moles.
Now that we know the moles of our products, let's plug some stuff into the ideal gas law PV = nRT. We are looking for P so let's solve for that. P = (nRT)/V, now let's plug in our values. Make sure V is converted to liters so 0.5 L. And convert celcius to kelvin by adding 273
P = ((0.204 moles)(318 K)(0.08206 L atm mol^-1 K^-1))/0.5 L
A lot of units cancel, and we get about 10.65 atm, if you don't want the answer in atm, you can find a conversion equation. But let's round to sig figs for now, which will bring us to 10 atm.
Answer:
![[SO_2Cl_2]=0.0175M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D0.0175M)
Explanation:
Hello!
In this case, considering that the decomposition reaction of SO2Cl2 is first-order, we can write the rate law shown below:
![r=-k[SO_2Cl_2]](https://tex.z-dn.net/?f=r%3D-k%5BSO_2Cl_2%5D)
We also consider that the integrated rate law has been already reported as:
![[SO_2Cl_2]=[SO_2Cl_2]_0exp(-kt)](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D%5BSO_2Cl_2%5D_0exp%28-kt%29)
Thus, by plugging in the initial concentration, rate constant and elapsed time we obtain:
![[SO_2Cl_2]=0.0225Mexp(-2.90x10^{-4}s^{-1}*865s)](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D0.0225Mexp%28-2.90x10%5E%7B-4%7Ds%5E%7B-1%7D%2A865s%29)
Best regards!
27 I think beacuse if you subtract
Hope you find this answer I need points
