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ICE Princess25 [194]
3 years ago
12

Select 2-possible ointment bases. Select one or more:

Chemistry
1 answer:
fredd [130]3 years ago
7 0

Answer:

The correct option is: c. petroleum jelly, d. Polyethylene glycol 4000/600 mixture                

Explanation:

Topical medications are used for the treatment of ailments and include ointments, gels, lotions creams etc. that can applied directly on the surface of the body i.e. skin.

An ointment base medication gets rapidly absorbed into the skin. Some of the examples of <u>ointment bases</u> include water-soluble bases: <u>polyethylene glycol</u>, hydrocarbon bases: <u>petroleum jelly</u>, paraffin wax.

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How many atoms are in 4.4 mol Zn?
nirvana33 [79]
1 mol zn ------------- 6.02x10²³ atoms
4.4 mol -------------- ??

4.4 x ( 6.02x10²³ ) / 1 => 2.648x10²⁴ atoms of zn
6 0
3 years ago
Write a resonance form for pyrrole in which nitrogen has a formal charge of 1. Are comparable resonance forms possible for pyrid
Svetach [21]

Answer:

See explanation and image attached

Explanation:

Here attached are resonance forms of pyrrole and pyridine. The images were obtained from quora and researchgate respectively.

Now, we can see that in the resonance forms of pyrrole, the nitrogen atom in the heterocycle has a formal charge of +1. However, in the six membered pyridine hetrocycle, the nitrogen atom may have a formal charge of -1 or +1 as shown in the canonical structures attached. The structures in which nitrogen has a +1 formal charge in pyridine are comparable to structures obtained from pyrrole. These structures have less contribution to the structure of pyridine.

3 0
3 years ago
Which statement describes the periodic table?
Nutka1998 [239]
Periodic table is a scientific model
6 0
3 years ago
Read 2 more answers
Determine the volume occupied by 2.5 mol of a gas at 18 °C if the pressure is 81.8 kPa?
mars1129 [50]

Answer:

74 litre

Explanation:

using ideal gas eqation PV=nRT

here P(pressure)=81.8 kPa =81.8×10^3 Pa

moles=2.5

temperature=273.15+18=291.15K

Gas constant R=8.314m^3-Pa/K-mol

now, V=nRT/P = 8.314×2.5×291.5/81.8×10^3 ≈74litre

✌️;)

3 0
3 years ago
How much heat, in joules, would be required to raise the temperature of 450g of Aluminum from 19.5 degrees Celsius to 31.2 degre
Evgesh-ka [11]

Answer:

Rtrt

Explanation:

How much heat, in joules, would be required to raise the temperature of 450g of Aluminum from 19.5 degrees Celsius to 31.2 degrees Celsius

3 0
4 years ago
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