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andre [41]
3 years ago
11

Which of the following is a form of antimatter?

Chemistry
2 answers:
Dominik [7]3 years ago
8 0
<span> the answer is .... D.Antineutrino ..

Hope it helps !!! 

</span>
Assoli18 [71]3 years ago
5 0
D. Antineutrino is the answer your looking for
You might be interested in
Jorge inflates a beach ball to a volume of 4L in his air-conditioned house where the temperature is 18℃. That afternoon he takes
balandron [24]

Answer:

The beach ball will get larger at the beach because the molecules are moving faster.

Explanation:

We can answer this problem by using Charle's Law, which states that:

"For a constant mass of an ideal gas kept at constant pressure, the volume of the gas is directly proportional to its temperature"

Mathematically:

V\propto T

where

V is the volume of the gas

T is the absolute temperature of the gas

Here, we are analyzing the air inside the ball (the gas). We are also told that when the ball is brought to the beach, the pressure does not change: therefore, we can apply Charle's Law.

We are told that when the ball is brought to the beach, the temperature increases from 18℃ to 32℃: therefore, since the volume of the air (and the ball) is proportional to the temperature, this means that the volume of the ball will increase as well.

The reason for this is that the ball is not thermally isolated, so the molecules of the air inside the ball reach soon the same temperature of the surroundings, and so they will move faster (higher temperature means higher average kinetic energy of the molecules, so the molecules move faster, and therefore the ball will expand).

So the correct option is

The beach ball will get larger at the beach because the molecules are moving faster.

8 0
4 years ago
Which liquid has the lowest vapor pressure at 65°C?
Paraphin [41]
- - <span>(1) ethanoic acid



</span>Ethanoic acid is the <span>liquid that has the lowest vapor pressure at 65</span>°<span>C




</span>
7 0
4 years ago
Read 2 more answers
What type of map projection makes plotting travel by airplane the easiest? I know it's azimuthal maps but why
KatRina [158]

Answer:

Explanation:

Azimuthal maps projection is the easiest for plotting travel by airplane because Azimuthal maps make the UV plane to be tangent to the globe and it's make the directions from the center of projections to be correct and accurate to any other points , likewise circles are also projected directly to the straight lines on the plane. And this is because Any line that is normally drawn through the tangent point give distance correctly and accurately.

7 0
3 years ago
Can someone plz help me on this. I need it really bad
kifflom [539]

Answer:

-  40.66

-  9.91

Explanation:

For the first question:

Our theoretical compound is MR₂

1 mol of MR₂ contains 1 mol of M and 2 moles of R

Let's find out the molar mass:

9.45 g/mol + 18.12 g/mol . 2 = 45.69 g/mol

We can solve this, by an easy rule of three:

1 mol of MR₂ weighs 45.69 grams

Then, 0.89 moles may weigh 40.66 g

For the second question:

Our theoretical compound is D₂G

Let's determine the molar mass:

11.45 g/mol . 2 + 44.57 g/mol = 67.47 g/mol

1 mol of anything contains 6.02×10²³ molecules. By this definition we can say that 6.02×10²³ molecules weigh 67.47 grams. Let's solve by the rule of three:

6.02×10²³ molecules weigh 67.47 g

8.84×10²² molecules may weigh (8.84×10²² . 67.47 ) / 6.02×10²³ = 9.91 g

8 0
3 years ago
The pH of a 0.1 M solution of an unknown weak acid is 3.7. What is the pKa of this acid?
Ahat [919]

Explanation:

Knowing the pH, you know the concentration of protons:

−log[H+]=pH=3.7

[H+]=10−3.7 M

Now, since the weak (monoprotic) acid dissociates into its conjugate base and a proton, the mols of protons are equimolar with the mols of conjugate base---the protons came FROM the weak acid, so the conjugate base that forms must be equimolar with the protons given out to the solvent.

HA⇌A−+H+

Hence, [A−]=[H+] in the same solution volume. Using the equilibrium constant expression, we get:

Ka=[H+]2eq[HA]eq

Don't forget that the HA form of HA had given away protons, so the mols of protons given away to generate A− is subtracted from the mols of (protons in) HA.

=[H+]2eq[HA]i−[H+]eq

=(10−3.7M)20.02M−10−3.7M

Ka=2.0105×10−6 M

8 0
3 years ago
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