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Alex Ar [27]
4 years ago
9

Sal recorded the number of crackers in each snack-sized package he opened. Which statement must be true according to the box plo

t? The data is symmetric, and the lowest number of crackers in a package was 7. The data is symmetric, and the lowest number of crackers in a package was 8. The data is skewed, and the lowest number of crackers in a package was 7. The data is skewed, and the lowest number of crackers in a package was 8.

Mathematics
2 answers:
Marina CMI [18]4 years ago
7 0

Answer:

The data is skewed, and the lowest number of crackers in a package was 7

Step-by-step explanation:

Hi,

First of all, since the question was incomplete due to the missing capture of the range shown on the box plot. I attached it for you so I could answer your question as well.

Taking into consideration the attached image's information, symmetric would be right down the middle, but it is not.

The image shows that it is <em>positively skewed with the lowest number being 7.</em>

Oduvanchick [21]4 years ago
6 0

Answer:

It is C

Step-by-step explanation:

Took the test

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A circle's radius that has an initial radius of 0 cm is increasing at a constant rate of 5 cm per second.
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a) r(t)=5t

b) A=\pi\cdot r^2

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d) A=25\pi  t^2

Step-by-step explanation:

We know that the circle is increasing its radio from an initial state of r=0 cm, at a rate of 5 cm/s.

This can be expressed as:

r(0)=0\\\\dr/dt=5\\\\r(t)=r(0)+dr/dt\cdot t=0+5t\\\\r(t)=5t

a) Radius of the circle, r (in cm), in terms of the number of seconds, t since the circle started growing:

r(t)=5t

b) Area of the circle, A (in square cm), in terms of the circle's radius, r (in cm):

A=\pi\cdot r^2

c) Circle's area, A (in square cm), in terms of the number of seconds, t, since the circle started growing:

A=\pi\cdot r^2\\\\A=\pi\cdot (5t)^2

d) Expanded form for the area A:

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