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igomit [66]
2 years ago
8

The scale of a map is 0.5 inch: 50 miles. on the map, the distance between two cities is 5 inches. what is that actual distance

between the two cities?
Mathematics
1 answer:
Kipish [7]2 years ago
4 0
.5 inch / 50 miles = 5 inches / x miles
x = 500 miles
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Find the rectangular coordinates of the point with the polar coordinates (3, 3 divided by 2 pi ). (1 point)
kifflom [539]

Answer:

The correct choice is (0,-3)

Step-by-step explanation:

To convert from polar coordinates to rectangular coordinates, we use the parametric equations:

x=r\cos \theta and y=r\sin \theta

The point given to us in polar coordinates is (3,\frac{3}{2}\pi).

where r=3,\theta=\frac{3\pi}{2}

x=3\cos (\frac{3\pi}{2}) and y=3\sin( \frac{3\pi}{2})

x=3(0) and y=3(-1)

x=0 and y=-3

The correct choice is (0,-3)

5 0
3 years ago
Let f(x) be a continuous function such that f(1) and f'(x)-Vx3 + 6. What is the value of,f(5)? (A) 11.446 (C) 24.672 (B) 13.446
tia_tia [17]

Answer:

f(5) = 26.672 which is option D

Step-by-step explanation:

From question, f(1) = 2 and f'(x)=√(x^3 + 6)

f(5) = f(1) + (5,1)∫ f'(x) dx

Integrating using the boundary 5 and 1;

f(5) = 2 + (5,1)∫√(x^3 + 6) dx

f(5) = 2 + 24.672

So f(5) = 26.672

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3 years ago
The following product, Estimate the answer. Explain your reasoning. Then Multiply each set of numbers for the answers.
sladkih [1.3K]

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Step-by-step explanation:

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2 years ago
What are the real zeros of x^3+4x^2-9x-36
Katyanochek1 [597]

Answer:

x = -4\\x = -3\\x = 3

Step-by-step explanation:

To find the real zeros you must match the function to zero and factor the expression.

We have a polynomial of degree 3.

We try to group the terms to perform the factorization

x ^ 3 + 4x ^ 2-9x-36 = 0\\\\x ^ 2(x + 4) - 9(x + 4) = 0

Now we take (x + 4) as a common factor

(x + 4)(x ^ 2 -9) = 0

If we have an expression of the form (a ^ 2-b ^ 2) we know that this expression is equivalent to:

(a ^ 2-b ^ 2) = (a + b)(a-b)

In this case

a = x\\b = 3

So:

(x ^ 2 -9) = (x + 3)(x-3)

Finally:

x ^ 3 + 4x ^ 2-9x-36 = (x + 4)(x + 3)(x-3) = 0

The solutions are:

x = -4\\x = -3\\x = 3

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