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Brrunno [24]
3 years ago
15

0.22/m = 0.05/3.7 please could you answer

Mathematics
2 answers:
Maslowich3 years ago
6 0

Answer:

16.28

Step-by-step explanation:

0.22/m=0.05/3.7

0.814/0.05=m

m=16.28

Alborosie3 years ago
4 0
16.28 is your answer
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HELP PLEASE it's my last one but I don't know how to do it..can somebody give me the answer and then explain how
xxTIMURxx [149]
Answer: 16,940 from interest.
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(2 x 1 )+ (6 x 1/1000) in a standard form
sveta [45]

Answer:

(2 x 1) + (6 x 1/1,000)  

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Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Answer the following Question
anastassius [24]

Answer:

a)$15.95

b) 8kg

Step-by-step explanation:

a)Approach this question by finding how much does it cost for 1g

So,

$2.1/50=$0.042per gram

then, multiple 380 to get the cost of sweets for 380 g

$0.042/gram*380gram=$15.96(Note: the gram cancel out each other)

Which is $15.95 as the question requested

b)This question stated that 3/4 of the metal has 15 kg

So, in order to find the total mass of metal we invert the 3/4 fraction

e.g 4/3*15=20kg

now we have the total mass we can find the mass for 2/5 of the metal

2/5*20kg=8kg

3 0
3 years ago
John and his friend ordered lunch at a local sandwich shop. They each ordered a soft drink that costs $1.65. John orders a whole
ExtremeBDS [4]

Answer:

a. $12.54 = $ 1.65 + c/2 + c b. $ 7.26

Step-by-step explanation:

a. What equation can you use to find the cost c of a sandwich

Let c be the cost of a whole ham sandwich. Now, the total bill = cost of drinks + cost of half a ham sandwich  + cost of a whole ham sandwich.

total bill = $ 12.54, cost of drinks = $ 1.65, cost of half a ham sandwich = c/2 and cost of a whole ham sandwich = c. So,

$12.54 = $ 1.65 + c/2 + c

b. What is the value of c

We then solve for c in the equation $12.54 = $ 1.65 + c/2 + c

collecting like terms, we have

$12.54 - $ 1.65 = c/2 + c

$ 10.89 = 3c/2

multiplying through by 2, we have

$ 10.89 × 2 = 3c

$ 21.78 = 3c

dividing through by 3, we have

c = $ 21.78/3

= $ 7.26

4 0
2 years ago
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