
Substract '-3.4x' at LHS nad the RHS of the above expression.

Add '4' on both LHS and RHs of the above expression.
Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Yes they are
. 90/150= 3/5
so 45/75 and 3/5.
1 because he HAD 5 and if he gave his friend 4 than he has 1 left, 5-4=1 my friend.
Yeshgggghhgfgggggggy. B be cc