Of the shape shown below. units? Show Calculator What is the answer

The length width and height of a rectangular solid are 8,4,1 respectively what is the length of the longest line segment whose e

LUCKY_DIMON [66]

Answer:

9 units

Step-by-step explanation:

Given

$Length = 8$

$Width = 4$

$Height = 1$

Required

Determine the length of the longest segment

To do this, we use:

$Longest = \sqrt{Length^2 + Width^2 + Height^2}$

So, we have:

$Longest = \sqrt{8^2 + 4^2 + 1^2}$

$Longest = \sqrt{64 + 16 + 1}$

$Longest = \sqrt{81}$

Take positive square root

$Longest = 9$

Hence, the length of the longest segment is 9 units

3 0

3 years ago

|x+5| = 3 |x-5| = 3 Please help NO LINKS

alexandr402 [8]

Answer:

the answer for |x+5|=3=x=-2and x=-8

and for the other one is x=8 and x=2

7 0

3 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago

Megan has $50 and saves $5.50 each week. Conner has $18.50 and saves $7.75 each week. After how many weeks will Megan and conner

QveST [7]

After 14 weeks, both Megan and Conner will have saved the same amount.

Step-by-step explanation:

Amount Megan have = $50

Amount saved each week = $5.50

Amount Conner have = $18.50

Amount saved each week = $7.75

Let,

x be the number of weeks.

According to given statement;

M(x) = 50+5.50x Eqn 1

C(x) = 18.50+7.75x Eqn 2

For amount to be same;

Eqn 1 = Eqn 2

$50+5.50x=18.50+7.75x\\50-18.50=7.75x-5.50x\\31.50=2.25x\\2.25x=31.50\\$

Dividing both sides by 2.25

$\frac{2.25x}{2.25}=\frac{31.50}{2.25}\\x=14$

After 14 weeks, both Megan and Conner will have saved the same amount.

Keywords: functions, division

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago

In circle P with mNRQ = 60°, find the angle measure of minor arc NQ

Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)$

Multiply by 2 on both sides.

$$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)$

$$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)$

Substitute m∠NRQ = 60°.

$$\Rightarrow 2\times 60^\circ=m(ar NQ)$

$$\Rightarrow 120^\circ=m(ar NQ)$

The measure of minor arc NQ is 120°.

8 0

3 years ago