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3 years ago

Two positive numbers have a difference of 4 and a product of 96. What are the numbers?

Mathematics

2 answers:

dolphi86 [110]3 years ago

7 0

Answer:

A. 12 and 8

Step-by-step explanation:

Let x be the larger positive number and y be the smaller positive number.

Since, the difference between these number is 4,

⇒ x - y = 4,

⇒ x = 4 + y ------(1)

Also, the product of these number is 96,

⇒ xy = 96

From equation (1),

$(4+y)y = 96$

$4y+y^2=96$

$y^2+4y-96=0$

$y^2+12y-8y-96=0$

$y(y+12)-8(y+12)=0$

$(y-8)(y+12)=0$

By zero product property,

y-8=0 or y+12=0

y = 8 or y = - 12( not possible )

Again from equation (1),

x = 4 + 8 = 12,

Hence, the numbers are 12 and 8,

Option A is correct.

Pavel [41]3 years ago

5 0

It'd be A.. You first would find which of them have a difference of 4. Which, is A, C, and D. Then, you'd multiply to see which of those three equal 96. 12*8=96

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