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scZoUnD [109]
2 years ago
6

Solve 3(b-5) = 27

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
6 0

Step-by-step explanation:

♤ 3(b-5) = 27

=> 3b - 15 = 27

=> 3b = 27 + 15 = 42

=> b = 42/3

=> <em><u>b</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>14</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u> </u></em>

♤ 2x/3 = 6

=> 2x = 6 × 3 = 18

=> x = 18/2

=> <em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>9</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u> </u></em>

♤ 2(n + 5) = 15

=> 2n + 10 = 15

=> 2n = 15 - 10 = 5

=> n = 5/2

=> <em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>5</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

♤ a + a + a + a = 24

=> 4a = 24

=> a = 24/4

=> <em><u>a</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>6</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

♤ 4c + 6 = 18

=> 4c = 18 - 6 = 12

=> c = 12/4

=> <em><u>c</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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A pair of socks costs $2.50 originally. The price is reduced to $1.75. What is the percent change?
telo118 [61]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

% change = difference / original x 100

% change = (0.75 / 2.5) x 100

% change = 30%

It was a 30% change

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∴ 3x² − 3x = -1

∴ x² − x = -1/3

∴ x² − x + (-1/2)² = (-1/2)² − 1/3

given x² + bx + (b/2)² = (x + b/2)²

∴ (x − 1/2)² = 1/4 − 1/3

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∴ x − 1/2 = ±i/(2√3)

∴ x − 1/2 = ±i√(3)/6

∴ x  = 1/2 ± i√(3)/6

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∴ x  = (3 − i√3)/6 and (3 + i√3)/6 <= the 2 complex roots

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Answer:

The cost of  4 pound of oranges is 500 and  equation represents the cost of C4P pounds of orange is y=\frac{375}{3} \times 4

Step-by-step explanation:

Let the cost of 1 pound oranges be x

Cost of 3 pound oranges = 3x

We are given that Cost of 3 lb oranges = 375

So, 3x=375

So, x =\frac{375}{3}

So, Cost of 1 pound of oranges = \frac{375}{3}

Let y be the cost of 4 pound oranges

Cost of 4 pound of oranges y =\frac{375}{3} \times 4

Cost of 4 pound of oranges y = 500

Hence The cost of  4 pound of oranges is 500 and  equation represents the cost of C4P pounds of orange is y=\frac{375}{3} \times 4

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What is the image?

Step-by-step explanation:

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Step-by-step explanation:

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Place numerator over common denominator: 57/100

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