0.38^• or 7/18. If the x after the g and before the i is a multiplication (btw the ^• is a repeater
First we would change the fractions into decimals and compare them. That way it would be easy to solve when needed.
1/2=0.50
5/8=0.625
1/8=0.125
Now we can see that 1/8 (0.125) is the smallest, followed by 1/2 (0.50), and 5/8 the largest. Now we can match the sizes with the insects.
Since the tiger beetle is the largest we will place that with the length of 5/8 since that is the largest.
The carpenter ant is second largest so it would be matched with 1/2
The aphid is the smallest so that would be with 1/8 as the smallest
*Hope that helped :D*
Based on the statement below, if d is the midpoint of the segment AC, the length of the segment AB is 4.5cm.
<h3>What is the line segment about?</h3>
in the question given,
AC = 3cm,
Therefore, AD and DC will be = 1.5cm segments each.
We are given C as the midpoint of segment DB.
So CB = 1.5cm.
The representation of the line segment is:
A-----------D------------C-------------B
1.5 1.5 1.5
Since AD, DC and CB are each 1.5cm segments. Then the equation will be:
= 1.5 + 1.5 + 1.5
= 4.5
Therefore, The length of the segment AB is 4.5cm.
See full question below
If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm.
Learn more about midpoint from
brainly.com/question/10100714
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In the balanced reaction
2 Fe + O₂ → 2 FeO
2 moles of iron (Fe) react with 1 mole of molecular oxygen (O₂) to produce 2 moles of iron oxide (FeO). The ratio of Fe to FeO is 1-to-1, so if one starts with 42.4 mol of Fe, one will end up with the same amount of FeO, 42.4 mol.
Look up the molar mass of Fe and O:
• Fe = 55.845 g/mol
• O = 15.999 g/mol
Then the molar mass of FeO is approximately 71.835 g/mol, and so the mass of 42.4 mol of FeO is
(42.4 mol) × (71.835 g/mol) ≈ 3050 g
Answer: 3/20
Step-by-step explanation: (1/7) :(20/21) = (1/7 )· 21/20 = 21/(7·20)= 3/20