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Mama L [17]
3 years ago
14

How lift force works in CER format

Physics
1 answer:
Step2247 [10]3 years ago
3 0
The really good answer is 30cm CER format
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This is the substance(s) formed in a chemical reaction. is called the products


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the average reaction time is 0.25 seconds.

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If element x has 88 protons, how many electrons does it have
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When a particle of mass m is at (x comma 0 )​, it is attracted toward the origin with a force whose magnitude is StartFraction y
Dahasolnce [82]

Answer:

W = y (b-a) / ab

Explanation:

Work is defined by the expression

W = ∫ F. dr

In this case the force is in the same direction of displacement, so the scalar product is reduced to the ordinary product

W = ∫ F dr

The expression of the strength left is

F = -y / x²

let's replace and integrate

W = ∫ (-y / x²) dx

W = -y (-1 / x)

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W = -y (-1 / b + 1 / a)

W = y (b-a) / ab

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8 0
3 years ago
A point charge q1 is at the center of a sphere of radius 20 cm. Another point charge q2 = 5 nC is located at a distance r = 30 c
valina [46]

Answer:

q_1 =7.08*10^{-9}C.

Explanation:

Gauss's Law says that the electric flux \Phi_E through a closed surface is directly proportional to the charge Q_{enc} inside it. More precisely,

$\Phi_E=\oint_S E\cdot dA = \dfrac{Q_{enc}}{\epsilon_0}. $

This means what is outside this closed surface S does not contribute to the flux through it because field lines that go in must come out, <em>resulting a zero flux from an external charge. </em>

In our context, this means the charge q_2 which is outside the sphere will have zero flux through the surface; therefore, Gauss's law will only be concerned with charge q_1 which is inside the sphere; Hence,

$\Phi_E=\oint_S E\cdot dA = \dfrac{q_1}{\epsilon_0} = 800 N\cdot m^2/C. $

Solving for q_1 gives

$ q_1= (800 N\cdot m^2/C)\epsilon_0, $

$ q_1= (800 N\cdot m^2/C)*(8.85*10^{-12}C^2/N\cdot m^2) $

\boxed{q_1 =7.08*10^{-9}C. }

which is the charge inside the sphere.

5 0
3 years ago
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