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yawa3891 [41]
3 years ago
11

If we could easily create machines or systems with no friction, what could we use them for?

Physics
1 answer:
Alexus [3.1K]3 years ago
3 0

Answer:

We could make a frictionless generator.

Explanation:

This would change life by making the cost for energy next to zero

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Can someone help me with this science question like uhm!??!? anyone
Anastaziya [24]

Answer:

mechanical layers of the earth

Lithosphere

-Asthenosphere

-Mesosphere

-Outer Core

-Inner Core

Chemical layers of the earth:

-Crust

-Mantle

-Core

I hope this helps :)

7 0
3 years ago
What includes a distance and a direction? A. Displacement B. Velocity C. Speed D. Acceleration
iren [92.7K]

hi <3

the correct option would be A. displacement. displacement is distance in a direction

hope this helps :)

7 0
3 years ago
Read 2 more answers
With certain exceptions, Class E airspace extends upward from either 700 feet or 1,200 feet AGL to, but does not include,A) 14,5
DedPeter [7]

Answer:

B) 18,000 feet MSL

Explanation:

There are three-dimensional parts in the navigation airspace in the world. The class E airspace is mostly used in the regions with coastal areas that are relatively populated. If we consider certain forms of exceptions, the class E airspace can move in the upward direction to few feet (i.e. 1200 ft). However, this doesn't include 18,000 feet MSL.

6 0
3 years ago
How many protons would the element with the atomic number 10 contain?
galben [10]
The atomic number is the same as the proton number so the answer would be D) 10
3 0
3 years ago
A capacitor is charged until its stored energy is 7.54 J. A second capacitor is then connected to it in parallel. If the charge
Ivan

Answer:

2 J

Explanation:

A charged capacitor of capacitance C_1 with energy of 7.54 J, is connected in parallel with another capacitor C_2 , so the charge is equally distributed between them.

(a) The energy stored in the capacitor before it being connected to the other capacitor is:

U_O=q_0^2/2C_1=7.54 J\\

The energy stored in the electric field is the sum of the energies of the two capacitors:

U=U_1+U_2\\U=q_1^2/2C_1+q_2^2/2C_2

since the charge equally distributed,  q_1 = q_2 = q_o/2. and since they are connected in parallel the potential difference on both of them is the same :

V_1=V_2\\q_1/C_1=q_2/C_2\\q_0/C_1=q_0/C_2\\C_1=C_2=C_3\\

hence,

U=q_0^2/8C+q_0^2/8C\\U=q_0^2/4C\\U=2J

8 0
3 years ago
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