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2 years ago

Is the sequence 3,6,9,12 geometric? True or false and why

1 answer:

7 0

This sequence is not a geometric.
It is because, common ratio = 6/3 = 2
9/6 = 1.5

As the ratio's are not same, it is not a G.P

Hope this helps!

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What is the area of the polygon H(3, 2), I(5, 2), J(5, 7), K(3, 7)

kobusy [5.1K]

Answer:

area = 10

Explanation:

8 0

3 years ago

The table below shows the number of tea bags needed to make different amounts of iced tea. What is the total number of quarts of

never [62]

Answer:

? = 6

Step-by-step explanation:

We can set up a proportion to find the solution.

$\frac{4}{16}=\frac{?}{24}$

$(24)\frac{4}{16}=\frac{?}{24}(24)$

$6=?$

Therefore, 24 tea bags makes 6 quarts of iced tea.

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2 years ago

What property is used in method 1?

Anvisha [2.4K]

Answer:

Division Property of Equality

Step-by-step explanation:

Divide both sides by 5

So answer : Division Property of Equality

6 0

3 years ago

Read 2 more answers

The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?

Jet001 [13]

Answer:

The roots are $x = (\frac{3}{2}, -2)$ , which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

In this question, we have that:

$2x^2 + x - 6 = 0$

Which is a quadratic equation with $a = 2, b = 1, c = -6$ . So

$\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49$

$x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}$

$x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2$

So the roots are $x = (\frac{3}{2}, -2)$ , which is given by option C.

3 0

3 years ago

Find the equation f(x) = a(x - h)2 + k for a parabola containing point (3, 6) and having (1, -2) as a vertex. What is the standa

nlexa [21]

f(x) = 2 $x^{2}$ -4x

Step-by-step explanation:

Step 1 :

Given, f(x) = a(x - h)2 + k

Point on the parabola is (3, 6)

Vertex (h,k) = (1,-2)

Step 2:

Substituting the vertex in the equation we have,

f(x) = a(x-1)2 -2

Substituting the point (3,6) in this we have,

6 = a(3-1)2 - 2 => 6 = 4a -2

=> 4a = 8 => a = 2

Step 3 :

Substituting the value for a and the vertex in the given equation we have

f(x) = 2(x-1)2 -2 = 2(x2 - 2x + 1) -2 = 2x2 - 4x

=> f(x) = 2 $x^{2}$ -4x which is the standard form

8 0

3 years ago