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MA_775_DIABLO [31]
3 years ago
5

Suppose the line segment whose endpoints are H(5,0) and I(-6,-3) is reflected over the y-axis. What are the coordinates H’I’?

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0

Answer:

H' = (-5, 0)

I' = (6, -3)

Step-by-step explanation:

Since you are reflecting the line segment across the y- axis, the rule would be (x, y) ---> (-x, y). So, applying the rule to H first, all you would need to do is change the sign of positive 5 to -5. And since the rule doesn't have the y- value change, it will stay the same as 0. So H' = (-5, 0)

Then onto I', you would apply the same rule to just the x- value, since according to the rule, the y-value doesn't get changed. So that would be turning -6 into a positive 6, this is because a negative × a negative =  a positive.

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Answer:

lateral area ≈ 668  m²

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Step-by-step explanation:

The lateral area of a triangular prism = perimeter of the base × height of the prism

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Base edges are 8m , 9m and 12.04m and height is 23 m.

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lateral area = (8 + 9 + 12.04) × 23

lateral area = 29.04 × 23

lateral area = 667.92  m²

lateral area ≈ 668 m²

Surface area

surface area = lateral area + 2B

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B = area of it triangular bases

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surface area = 667.92   + 2(1/2 × base × height)

surface area = 667.92  + 2(1/2 × 8 × 9)

surface area = 667.92  + 2(1/2 × 72)

surface area = 667.92  + 2(36)

surface area = 667.92  + 72

surface area = 739.92  

surface area ≈ 740 m²

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Step-by-step explanation:

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