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nignag [31]
3 years ago
5

67 pts who ever answers wins. its a photo

Mathematics
1 answer:
leonid [27]3 years ago
4 0

Since angles 3 and 2 are congruent, angle 2 is 112 degrees. Also, because angles 2 and 1 are vertical angles, they'll have the same measurement.

So m<1=112 degrees

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A figure has vertices at L(3,3), M(2,4), and N(−1,0). After a transformation, the image of the figure has vertices at L′(2,−5),
alexandr402 [8]

The transformation was a reflection over the line x = -0.5

And the image and preimage can be seen in the graph below.

<h3>How to identify the preimage and image?</h3>

First, the original vertices are:

L(3, 3)

M(2, 4)

N(-1, 0)

3 vertices means that our figure is a triangle.

Now, the transformed vertices are:

L'(2, -5)

M'(3, -4)

N'(-1, 1)

And the graph of both sets can be seen below.

Now we can try to identify the transformation.

Now, notice that all the points (L, M, N, L', N', M') are equidistant to the horizontal line x = -0.5

This is a clear implication that the transformation was a reflection over the line x = -0.5

If you want to learn more about transformations:

brainly.com/question/4289712

#SPJ1

3 0
1 year ago
Some friends played a board game. During the​ game, one unlucky player had to move back 8 spaces 5 turns in a row. Find a number
mojhsa [17]

Answer:

I think that it would be -40

Step-by-step explanation:

I think this because they had to go back 40 spaces because 8 x 5 = 40.

7 0
3 years ago
Solve<br> 15x +4&lt; 26.5<br> Need help fast pls
d1i1m1o1n [39]

Answer:

x<1.5

explanation: move 4 to other side subtract it with 26.5 then divide it by 15

5 0
2 years ago
Read 2 more answers
I just need the final answer. thanks! :)
aleksandr82 [10.1K]
4 miles per hour I think
5 0
3 years ago
If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
harina [27]

Answer:

10

Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

8 0
3 years ago
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