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lukranit [14]
4 years ago
15

What does it mean when you round to the nearest half

Mathematics
1 answer:
Marysya12 [62]4 years ago
7 0

Answer: Round to the nearest multiple of 1/2.

Step-by-step explanation:

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115/12

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Points A, B, C and D have coordinates A(5, 7), B(7, 1), C(17, m) and D(−1, 3). If line
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3

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What is 5.092 rounded to the nearest hundredth?
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Evaluate if m=1 and n=2 what’s 15m/n+1-m^2+n
Jobisdone [24]

\\ \sf\longmapsto \dfrac{15m}{n}+1-m^2+n

\\ \sf\longmapsto \dfrac{15(1)}{2}+1-(1)^2+2

\\ \sf\longmapsto \dfrac{15}{2}+3-1

\\ \sf\longmapsto \dfrac{15}{2}+2

\\ \sf\longmapsto \dfrac{15+4}{2}

\\ \sf\longmapsto \dfrac{19}{2}

7 0
3 years ago
From A to B a private plane flies 2.8 hours at 110 mph on a bearing of 64 degrees . It turns at point B and continues another 1.
Firdavs [7]

Answer:

a. 360.323 m

b. 95.265^{o}

Step-by-step explanation:

Distance covered from A to B = speed x time

                                                 = 110 x 2.8

                                                 = 308 m

Distance covered from B to C = speed x time

                                                  = 110 x 1.7

                                                  = 187 m

The sum of angles at B = 64^{o} + 26^{o}

                                       = 90^{o}

a. The distance of the plane from it starting point to C can be determined by applying the cosine rule.

b^{2} = a^{2} + c^{2} - 2ac Cos B

Sot hat;

b^{2} = 187^{2} + 308^{2} - 2(187 x 308) Cos 90^{o}

But, Cos 90^{o} = 0

So that,

b^{2} = 187^{2} + 308^{2}

  = 34969 + 94864

  = 129833

b = \sqrt{129833}

  = 360.323

The distance from A to C is 360.323 m.

b. Applying the sine rule;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{187}{SinA} = \frac{360.323}{Sin90^{o} }

\frac{187}{SinA} = \frac{360.323}{1}

Sin A = \frac{187}{360.323}

         = 0.5190

⇒ A = Sin^{-1} 0.5190

       = 31.265^{o}

The bearing of the plane from its original location = 64^{o} + 31.265^{o}

                                                     = 95.265^{o}

8 0
3 years ago
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