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Alja [10]
4 years ago
6

Suzanne can work 10 math problems in 15 minutes. How many can she work in an hour and a half?

Mathematics
2 answers:
QveST [7]4 years ago
6 0

90/15=9

9*10=90

so your answer would be 90

ASHA 777 [7]4 years ago
5 0
135 problems
or 60 problems
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What is the value of x?
rodikova [14]

Answer:

30°

Step-by-step explanation:

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3 years ago
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Can someone help me solve #9!?
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Dy/dx = (4y²)(x⁴/³)

Find ∫(4y²)(x⁴/³) =∫(4y²∛(x⁴)dx = 3∛(x⁴).y² +c or 3x⁴/³.y² + c
4 0
3 years ago
Eight more than.twice an number is four less than the same number
In-s [12.5K]

Answer:

2x+8=x-4

Step-by-step explanation:

I think that's right, let me know if it's wrong and I'll delete

7 0
3 years ago
How are these triangles congruent?
ICE Princess25 [194]

Answer:

\triangle PTY \cong \triangle PSQ by ASA

Step-by-step explanation:

In triangle PTU and triangle PSQ

\overline{PT} \cong \overline{PS}     [Side]             [Given]

\angle PTU \cong \angle PSQ          [Angle]

Vertical angles are those angles which are opposite to each other.

\angle TPU \cong \angle SPQ        {Angle]

ASA(Angle-Side-Angle) postulates states if two angles and one included  side of one triangle are congruent to two angles and the included side of the other triangle, then these triangle are congruent.

by ASA postulates;

\triangle PTY \cong \triangle PSQ


5 0
4 years ago
Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card
Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0
4 years ago
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