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3 years ago

Can someone please help me with this question I’m stuck on

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

6 0

Answer:

The answer is option D.

Hope this helps

Rom4ik [11]3 years ago

3 0

Answer:

Step-by-step explanation:

X-5 is not a factor because is a reminder and 5 is not a zero because

p ( 5)=4

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the volume V of a gas at a constant temperature varies inversely with the pressure P. when the volume is 100 cubic inches the pr

fiasKO [112]

Answer:

The pressure is $20\ psi$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

In this problem we have

$V*P=k$

where

V is the volume of a gas at a constant temperature

P is the pressure

we have

For $V=100\ in^{3}$ , $P=25\ psi$

step 1

Find the value of k

substitute the values of V and P

$100*25=k$

$k=2,500$

The equation is equal to $V*P=2,500$

step 2

Find the pressure when the volume is 125 cubic inches

For $V=125\ in^{3}$

substitute in the equation and solve for P

$125*P=2,500$

$P=2,500/125=20\ psi$

8 0

3 years ago

Which of the following is equivalent to sec2θ−1sec2θ for all values of θ for which sec2θ−1sec2θ is defined?

galina1969 [7]

Answer:

$2 sin^2 \theta$

Step-by-step explanation:

According to the scenario, the following information is given:

$= \frac{sec^2 \theta - 1 }{sec^2 \theta}$

$= (\frac{1}{\frac{cos^2\theta}{\frac{1}{cos^2\theta} }} - 1)$

$= 1 - cos^2\theta\\\\= 1 - (1 - 2 sin^2 \theta)\\\\= 2 sin^2 \theta$

Therefore for the given equation, the answer is $2 sin^2 \theta$

5 0

3 years ago

214512154515454521545*4515546254-28452548554/515252845262-28482+284825425784541=5485152x+465555595656

Assoli18 [71]

Answer: hay im back

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Just Need A Few Questions Answered To Finish My Quiz, Any Help Would Be Much Appreciated.

kvv77 [185]

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

$\frac{4}{8}=\frac{1}{2}$

The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

$P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)$ $Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)$ $R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)$

Then triangle P''Q''R'' has coordinates

P''(-4,0)

Q''(-3,1)

R''(1,-2)

Part C:

PQR is congruent to P''Q''R''?

Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.

Then the triangles are not congruent

8 0

10 months ago

Help asappppp hbshhshshhshshsshshshs

SVEN [57.7K]

9 on the top as well so 9 x 2 18 3x2 6 3

8 0

3 years ago