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3 years ago

Factor by grouping. 4x^3 − 16x^2 + 12 − 3x

1 answer:

5 0

He first thing that we would really want to consider is that we would definitely want to group this up because it would make things a lot more easier.

$(((4 * (x^3)) - 2^4x^2) + 12) - 3x \\ \\ as \ we \ simplify \ this . . . \\ \\ ((2^2x^3 - 2^4x^2) + 12) - 3x \\ \\ Factoring: \ \boxed{4x^3-16x^2-3x+12 } \\ \\ Factoring: \ 4x^2-3 \\ \\$

Your answer: $\boxed{\bf{ (4x^2 - 3) *(x - 4)}}$

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What is 0.08 written as a percent

andrew11 [14]

0.08 can be written as 8%

3 0

2 years ago

Read 2 more answers

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

7 0

3 years ago

Please help with this, thank you!

dezoksy [38]

Step-by-step explanation:

$\sqrt{1.8 \times \sin(46 ) \div 7.8 {}^{2} } - 50.8 \\ \sqrt{1.8} \times 0.72 \div 60.84 - 50.8 \\ \sqrt{1.29 \div 10.04 } \\ \sqrt{0.128 } \\ 0.358$

8 0

2 years ago

Evaluate r s + 14s when r= 6 and s= 1/4

arlik [135]

R S + 14(S) R=6 S=1/4
(6)(1/4) + 14(1/4)
1.5 + 14(1/4)
1.5 + 3.5
5

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3 years ago

Why is there an AA similarity postulate but not an AA congruence postulate

bagirrra123 [75]

Answer:

Step-by-step explanation:

4 0

2 years ago