Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
Answer A. 15 glad to help
Let us evaluate each pair of expressions one at a time.
8. (n²+4) - n² and 4n.
(n²+4) - n² = n²+ 4 - n² = 4 which is not equal to 4n.
NOT EQUIVALENT
9. 3x + 5 and 2(x + 3)
2(x + 3) = 2x + 6 which is not equal to 3x + 5.
NOT EQUIVALENT
10. 15 - 6x and 15(1 - 6x)
15(1 - 6x) = 15 - 90x which is not equal to 15 - 6x
NOT EQUVALENT
11. (y + y + 2 + y) + 3y and 6y + 2
(y +y +2 + y) + 3y = y+y+y +2 + 3y = 3y + 2 + 3y = 6y + 2.
It matches the other expression.
EQUIVALENT
12. 8y - 3 + 10y and 3(6 - 1)
8y - 3 + 10y = 8y + 10y - 3 = 18y - 3
3(6 - 1) = 3(5) = 15
The two expressions do not match.
NOT EQUIVALENT.
Answer: Only the expressions in number 11 are equivalent.
Answer:
4
Step-by-step explanation:
Root(48)/Root(3)
= root(48/3)
= root(16)
=4
