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xz_007 [3.2K]
4 years ago
14

Factor by grouping. 4x^3 − 16x^2 + 12 − 3x

Mathematics
1 answer:
AleksAgata [21]4 years ago
5 0
He first thing that we would really want to consider is that we would definitely want to group this up because it would make things a lot more easier.

(((4 * (x^3)) -  2^4x^2) +  12) -  3x \\ \\ as \ we \ simplify \ this . . . \\ \\  ((2^2x^3 -  2^4x^2) +  12) -  3x \\ \\ Factoring:  \ \boxed{4x^3-16x^2-3x+12 } \\ \\ Factoring: \  4x^2-3 \\ \\

Your answer: \boxed{\bf{  (4x^2 - 3) *(x - 4)}}
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4 - 3x = 8 - 4x Plz answer this question
timurjin [86]

Answer:x=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4−3x=8−4x

4+−3x=8+−4x

−3x+4=−4x+8

Step 2: Add 4x to both sides.

−3x+4+4x=−4x+8+4x

x+4=8

Step 3: Subtract 4 from both sides.

x+4−4=8−4

x=4

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