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xz_007 [3.2K]
3 years ago
14

Factor by grouping. 4x^3 − 16x^2 + 12 − 3x

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0
He first thing that we would really want to consider is that we would definitely want to group this up because it would make things a lot more easier.

(((4 * (x^3)) -  2^4x^2) +  12) -  3x \\ \\ as \ we \ simplify \ this . . . \\ \\  ((2^2x^3 -  2^4x^2) +  12) -  3x \\ \\ Factoring:  \ \boxed{4x^3-16x^2-3x+12 } \\ \\ Factoring: \  4x^2-3 \\ \\

Your answer: \boxed{\bf{  (4x^2 - 3) *(x - 4)}}
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