Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
Answer:
-16
Step-by-step explanation:
Answer:
y intercept = (0,-2)
x intercept = (-2,0)
Step-by-step explanation:
For y intercept, plug 0 for x
y = (0) - 2
y = -2
y intercept = -2
For x intercept, plug 0 for y
(0) = -x - 2
Move -2 to other side
-x = 2
Since x is negitave, make 2 negitave
x = -2
x intercept = -2
.08 x .04 is the right answer
Answer:
A.481.25
Step-by-step explanation:
d=rt
Plug in numbers
d=38.5(12.5)
d=481.25
