Factor by grouping. 4x^3 − 16x^2 + 12 − 3x

1 answer:

5 0

He first thing that we would really want to consider is that we would definitely want to group this up because it would make things a lot more easier.

$(((4 * (x^3)) - 2^4x^2) + 12) - 3x \\ \\ as \ we \ simplify \ this . . . \\ \\ ((2^2x^3 - 2^4x^2) + 12) - 3x \\ \\ Factoring: \ \boxed{4x^3-16x^2-3x+12 } \\ \\ Factoring: \ 4x^2-3 \\ \\$

Your answer: $\boxed{\bf{ (4x^2 - 3) *(x - 4)}}$

You might be interested in

The picture shows the Alamillo bridge in Seville, Spain. In the picture m<1=58 and m<2=24. Find the measure of the supplem

Anna11 [10]

Answer:

Supplement of <1 = 122°

Supplement of <2 = 156°

Step-by-step explanation:

Two pairs of angles are said to be supplementary, if their measures in degrees add up to give us 180°. A supplement of am angle is simply 180° - the measure of that angle.

Given that meadure of angle 1 = 58°, the supplement of angle 1 = 180° - 58° = 122°

Also, if the measure of angle 2 = 24°, the supplement of angle 2 = 180° - 24° = 156°.

Thus:

Supplement of <1 = 122°

Supplement of <2 = 156°

6 0

3 years ago

2.c)in the diagram below, 4 m and ORIST at R. 5 $ 0 If m_1 = 63, find m_2.

pickupchik [31]

Data:

l and m are parallel lines

QR and ST are perpendicular in R

Angle 1 is 63°

The angle formed by perpendicular lines is a right angle (90°)

Angles 1 and 3 are alternate angles: angles that occur on opposite sides of a transversal line that is crossing two parallel.

Alternate angles are congruent, have the same measure.

$\begin{gathered} m\angle1=m\angle3 \\ \\ m\angle3=63 \end{gathered}$

The sum of the interior angles of a triangle is always 180°. In triangle QRT:

$\begin{gathered} m\angle2+m\angle3+90=180 \\ \\ m\angle2+63+90=180 \\ \\ m\angle2+153=180 \end{gathered}$

Use the equation above to find the measure of angle 2:

$\begin{gathered} \text{Subtract 153 in both sides of the equation:} \\ m\angle2+153-153=180-153 \\ \\ m\angle2=27 \end{gathered}$ Then, the measure of angle 2 is 27°