Ask question

Ask question

All categories

2 years ago

5

A man who is 2 meters tall stands on level ground. He is 32 meters from the base of a tree. The angle of elevation of the top of

the tree from his line of sight is 25 degrees. Which equation can be used to solve for the height of the tree? (h = height of the tree)

2 answers:

podryga [215]2 years ago

6 0

Answer:

h = 16.92 m

Step-by-step explanation:

If you mean to man horizontal line of sight then the height of the tree is:

h = 2m + x

x is one right side and second is distance from the base of a tree 32m.

Tangence in this right triangle is:

tan 25° = x / 32 => x = 32 · tan 25° = 32 · 0.4663 = 14.92m

h = 2 + 14.92 = 16.92m

God with you!!!

valentinak56 [21]2 years ago

5 0

Answer:

H=16.92 (MARK ME AS BRAINIEST)

Step-by-step explanation:

The side opposite 25° is the height of the tree. The side adjacent to 25° is the distance the man is standing from the tree.

tan 25°=

opposite side

adjacent side

Let h-2 represent the height of the tree

h - 2) = 32 tan 25°

h - 2 = 14.92

h = 16.92 meters

You might be interested in

The temperature in frostburg is -7.This is 18 less than the temperature in coldspot.Find the temperature of coldspot

Drupady [299]

If the temperature in frostburg is 18 less than the temperature in coldspot, then the following equation compares the two temperatures:

$f = c-18$

where $f,c$ are the temperatures in frostburg and coldspot. Since we're given $f$ , we can solve for $c$ :

$-7 = c-18 \iff c = -7+18 = 11$

6 0

3 years ago

How do you know that 5.5 is to the right of 5 1/4 on the number line

Mamont248 [21]

Because it is greater, larger numbers are on the right of the number line...

4 0

2 years ago

Read 2 more answers

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

Pleaseee help, question what is the sum of 4x^2 + 2x - 5 and 7x^2 - 5x + 2

Nataliya [291]

Simplification of polynomials.

Polynomials <em>are</em> mathematical expressions made up of many terms.<em>To</em> simplify a polynomial <em>the most, you must collect all</em><em> </em>like terms <em>and rearrange them from highest to lowest power.</em>

<h3>4x² + 2x -5 + 7x² - 5x+2</h3><h3>4x² + 2x -3 + 7x² - 5x+2</h3><h3>11x² + 2x - 3 - 5x</h3><h3>11x² - 3x - 3 ====> Option "A"</h3>

6 0

11 months ago

Read 2 more answers

A baby elephant weighs 250 lb,

Sladkaya [172]

Tons would be 0.125
and Kg would be 113.636

5 0

3 years ago