Answer:
1,620/.60 = $2,700
step-by-step explanation:
Calculate the complement of the trade discount 100% - 40 = .60 •Calculate the list price $n Discount Rates EXAMPLE: The list price of the office equipment is $15,000. The chain discount is 20/15/10.Step 1. $15,000 X .20 =$3,000Step 2. $15,000-3,000=$12,000 X .15 = $1,800Step 3. $12,000-1,800 = $10,200 X.10 = $1,020Step 4. $10,000- 1,020 = 9,180 Net PriceCalculating Net Price Using Net Price Equivalent Rate EXAMPLE: The list price of office equipment is $15,000. The chain discount is 20/15/10. What is the net price? Step 1. Calculate each rates complement and convert to a decimal.100%-20 = 80% which is .8100%-15= 85% which is .85100% -10 = 90% which is .9Step 2. Calculate the net price equivalent rate. ( Do not round ).8 X .85 X .9 = .612 Net price equivalent rate. For each dollar you are spending about 60 cents.Step 3. Calculate the net price (actual cost to buyer) $15,000 X .612 = $9,180Step 1. Subtract each chain discount rate from 100% (find the complement) and convert each percent to a decimal.Trade Discount AmountList price x Trade discount rate = Trade discount amount $5,678 x 25% = $1,419.50Net Price List price -- Trade discount amount = Net Price
1/2+1/2=2/2=1 so 1/2 was eaten and the other half was leftovers.
Answer:
This would be non linear
Step-by-step explanation:
Because a linear is a straight line
this would not equal to a straight line so it is non linear
have a nice day uvu
There are 9 cans of soup and 5 cans of frozen dinner.
The variables used for soup and frozen dinner are x and y respectively.
Step-by-step explanation:
Let,
Soup = x
Frozen Dinner = y
According to given statement of sodium;
300x + 500y = 5200 eqn 1
And,
x + y = 14 eqn 2
Subtracting Eqn 3 from Eqn 1;
Putting value of y in Eqn 1;
There are 9 cans of soup and 5 cans of frozen dinner.
The variables used for soup and frozen dinner are x and y respectively.
Keywords: Variables, linear equations, subtraction.
Learn more about linear equations at;
#LearnwithBrainly
X^2-9=-5
x^2-4=0
(x+2)(x-2)=0 [Difference of Two Squares]
x=-2,2
-2 is the smaller root.
