Answer:-4
Step-by-step explanation:
According to the given descriptions to create a figure of lines, the answer is transitive property. Transitive property relates two angles that are separately proven by different theorems and making a statement that connects or relates the congruence of two angles or even two sides.
Answer:
x=9
Step-by-step explanation:
Solve for x
(
x
+
2
3
x
)
−
1
3
(
x
+
2
3
x
)
=
10
Simplify
x
+
2
3
x
−
1
3
⋅
(
x
+
2
3
x
)
.
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Simplify each term.
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x
+
2
x
3
−
5
x
9
=
10
Find the common denominator.
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x
⋅
9
9
+
2
x
⋅
3
9
−
5
x
9
=
10
Combine fractions with similar denominators.
x
⋅
9
+
2
x
⋅
3
−
5
x
9
=
10
Subtract
5
x
from
x
⋅
9
.
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2
x
⋅
3
+
4
⋅
x
9
=
10
Multiply
3
by
2
.
6
x
+
4
⋅
x
9
=
10
Add
6
x
and
4
⋅
x
.
10
x
9
=
10
Multiply both sides of the equation by
9
10
.
9
10
⋅
10
x
9
=
9
10
⋅
10
Simplify both sides of the equation.
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Simplify
9
10
⋅
10
x
9
.
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x
=
9
10
⋅
10
Cancel the common factor of
10
.
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Cancel the common factor.
x
=
9
10
⋅
10
Rewrite the expression.
x
=
9
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
Powerpoint
Step-by-step explanation:
I think that a powerpoint presentation would be best. With the first slide, put the picture and a title. With each slide, put more than one word and maybe an example. Make it colorful and maybe put some math puns in some of them.
Hope this helps.