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AnnyKZ [126]
4 years ago
15

More points!! Please solve 22 and 23

Mathematics
1 answer:
nadya68 [22]4 years ago
8 0
For the table, we can count the circles that appear in each step of the fractal. The center is a single circle and is step 0. Step 1 sees 4 circles grow off of that one circle. Step 2 sees 4 circles grow off of each of these circles. Therefore the table should be:

Step 0 : 1 circle
Step 1 : 4 circles
Step 2 : 16 circles
Step 3:  64 circles

Using this table, we can solve the second part. This function is exponential growth and each step is a multiple of 4. Therefore, the function is f(x) = 4^x.
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Last one!! I need the steps please! Will mark brainliest!
hoa [83]

Answer:

h(t)=-6(t-2)^2+24

Step-by-step explanation:

Given function:

h(t)=-6t^2+24t

where:

  • h = height (in feet)
  • t = times (in seconds)

Rewrite in the form h(t)=a(t-h)^2+k

The quickest way to do this is to expand h(t)=a(t-h)^2+k and compare coefficients with the original function.

\begin{aligned}h(t)& =a(t-h)^2+k\\ & = at^2-2aht+ah^2+k\end{aligned}

Comparing coefficients with h(t)=-6t^2+24t

\begin{aligned}\implies at^2& =-6t^2\\ a &=-6\end{aligned}

\begin{aligned}\implies -2aht & =24t\\ -2(-6)ht& =24t\\ 12ht & = 24t\\ 12h & = 24\\ h & = 2\end{aligned}

\begin{aligned}\implies ah^2+k & = 0\\(-6)(2)^2+k &=0\\ -24+k & =0\\ k &=24 \end{aligned}

Therefore, substituting the found values into the equation:

h(t)=-6(t-2)^2+24

6 0
2 years ago
If sin Θ = 2 over 3 and tan Θ < 0, what is the value of cos Θ?
guapka [62]
If sin Θ is positive and tan Θ is negative, then the angle should be in the second quadrant using the rule of thumb. In this case, cos Θ is expected to be negative. Using the calculator, the answer is -0.7454. This is equivalent to option D. <span>negative square root of 5 over 3</span>
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3 years ago
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Answer:

8.57% rebate

Step-by-step explanation:

100 / 35 = 2.85714285714

2.85714285714 * 3 = 8.57142857143

8.57142857143 ---> 8.57%

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Step-by-step explanation:

1.018 × 0.028 = 0.028594

↑

Increase of money not total

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Jobisdone [24]
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