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Vanyuwa [196]
3 years ago
13

I need help finding the value of x. Please help me ?

Mathematics
1 answer:
prisoha [69]3 years ago
4 0

Answer:

79 + 51 + _ = 180

x = 50 degrees

Step-by-step explanation:

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find the percent of decrease from 210 to 120. round to the nearest tenth if necessary. A. 75% B. 42.9% C. 0.8% D. 175%​
abruzzese [7]

Answer:

42.9%

Step-by-step explanation:

-42.857142857142854 is the exact number. Rounded to 42.9% thus b: is the correct answer.

Formula:

[(120 - 210) / 210] × 100% = -0.42857142857142855 × 100% = -42.857142857142854%

8 0
4 years ago
The two-way table shows the medal count for the top-performing countries in the 2012 Summer Olympics. A 5-column table has 5 row
LUCKY_DIMON [66]

Which statement is true?

  • The probability that a randomly selected silver medal was awarded to Great Britain is StartFraction 17 Over 99 EndFraction.
  • The probability that a randomly selected medal won by Russia was a bronze medal is StartFraction 32 Over 103 EndFraction.
  • The probability that a randomly selected gold medal was awarded to China is StartFraction 88 Over 137 EndFraction.
  • The probability that a randomly selected medal won by the United States was a silver medal is StartFraction 104 Over 339 EndFraction.

Answer:

(A)The probability that a randomly selected silver medal was awarded to Great Britain is 17/99.

Step-by-step explanation:

The table is given below:

\left|\begin{array}{l|c|c|c|c|c}  &Gold&Silver          & Bronze       &Total\\United States    &46      &    29      &          29      &         104\\China             &     38     &     27       &         23        &         88\\Russia         &        24  &        26      &          32                 &82\\Great Britain   &    29   &        17        &        19        &         65\\&&&&&\\Total                    &137     &     99     &          103      &        339\end{array}\right

                         

We calculate the probabilities given in the statements.

(A) The probability that a randomly selected silver medal was awarded to Great Britain

= 17/99

(B)The probability that a randomly selected medal won by Russia was a bronze medal

=32/82

(C)The probability that a randomly selected gold medal was awarded to China

=38/137

(D)The probability that a randomly selected medal won by the United States was a silver medal

=29/104

We can see that only the first statement is true.

5 0
3 years ago
Read 2 more answers
You are selling candy and wrapping paper for the band's Christmas fundraiser. The candy sells for 8 dollars per box and the wrap
Ludmilka [50]

Answer:

The number of boxes of candy sold is 4

The number of rolls of wrapping paper sold is 10

Step-by-step explanation:

Let x = number of boxes of candy that was sold.

Let y = number of rolls of wrapping paper was sold.

The candy sells for 8 dollars per box and the wrapping paper sells for 6 dollars per roll. This means that x boxes of candy and y rolls of wrapping paper will be sold for

$(8x + 6y)

If you have sold 14 items, and collected 92 dollars, this means that

x + y = 14

8x + 6y = 92 - - - - - - -1

Substituting x = 14 - y into equation 1, it becomes

8(14-y) + 6y = 92

112 - 8y + 6y = 92

- 8y + 6y = 92 - 112

-2y = -20

y = 20/2 = 10

x = 14 - y

x = 14 - 10

x = 4

The number of boxes of candy sold is 4.

The number of rolls of wrapping paper sold is 10.

7 0
3 years ago
Write three ratios equivalent to the given ratio.include the simplest form if not given.circle the simplest form.10/12
kobusy [5.1K]
The simplest form is 5/6, an equivalent ratio is 20/24 and another is 30/36
7 0
3 years ago
Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
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