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stiks02 [169]
3 years ago
10

This is what I need help with can someone please give me it it's a homework I don't get

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0
The answer looks like it's A.
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A demographer is investigating various populations to find out how they use resources. She wants to select the population that u
horrorfan [7]

Answer:

She should select an industrial society (industrial population)

Step-by-step explanation:

An industrial society is a society that owes its operations to the use of technology which supports human usage of resources that allows high production turnouts.

An industrial society has high liking le preference for large population with a high capacity for external energy sources (e.g.fossil fuels) which in directly or indirectly increases the rate which resources are being used and also scale of production.

The resources could be human (labour) natural resources such as water, air, coal, natural gas, coal, etc. and it could also be technology advancements.

7 0
3 years ago
The planets in our solar system do not travel in circular paths. Rather, their orbits are elliptical. The Sun is located at a fo
qwelly [4]

1. The distance between the perihelion and the aphelion is 116 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Step-by-step explanation:

Let us revise the equation of the ellipse is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where the major axis is parallel to the x-axis

  • The length of the major axis is 2a
  • The coordinates of the vertices are (± a , 0)
  • The coordinates of the foci are (± c , 0) , where c² = a² - b²

∵ The Sun is located at a focus of the ellipse

∴ The sun located ate c

∵ The perihelion is the point in a planet’s orbit that is closest to the

   Sun ( it is the endpoint of the major axis that is closest to the Sun )

∴ The perihelion is located at the vertex (a , 0)

∵ The closest Mercury comes to the Sun is about 46 million miles

∴ The distance between a and c is 46 million miles

∵ The aphelion is the point in the planet’s orbit that is furthest from

   the Sun ( it is the endpoint of the major axis that is furthest from

   the Sun )

∴ The aphelion is located at the vertex (-a , 0)

∵ The farthest Mercury travels from the Sun is about 70 million miles

∴ The distance from -a to c is 70 million miles

∴ The distance between the perihelion and the aphelion =

   70 + 46 = 116 million miles

1. The distance between the perihelion and the aphelion is 116 million miles

∵ The distance between the perihelion and the aphelion is the

  length of the major axis of the ellipse

∵ The length of the major axis is 2 a

∴ 2 a = 116

- Divide both sides by 2

∴ a = 58

∴ The distance from the center of Mercury’s elliptical orbit to the

   closest end point to the sun is 58 million miles

∵ The distance between the sun and the closest endpoint is

   46 million miles

∴ The distance from the center of Mercury’s elliptical orbit and

   the Sun = 58 - 46 = 12 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

∵ The major axis runs horizontally

∴ The equation is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

∵ a = 58

∵ c is the distance from the center to the focus of the ellipse

∴ c = 12

∵ c² = a² - b²

∴ (12)² = (58)² - b²

- Add b² to both sides

∴ (12)² + b² = (58)²

- Subtract (12)² from both sides

∴ b² = (58)² - (12)² = 3220

- Substitute these values in the equation

∴ \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

The eccentricity (e) of an ellipse is the ratio of the distance from the

center to the foci (c) and the distance from the center to the

vertices (a) ⇒ e=\frac{c}{a}

∵ c = 12

∵ a = 58

∴ e=\frac{12}{58} = 0.207

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

If the eccentricity is zero, it is not squashed at all and so remains a circle.

If it is 1, it is completely squashed and looks like a line

∵ The eccentricity of the ellipse is 0.207

∵ This number is closed to zero than 1

∴ The shape of the ellipse is near to the shape of the circle

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Learn more:

You can learn more about conics section in brainly.com/question/4054269

#LearnwithBrainly

5 0
3 years ago
Part A From the choices provided, select all the questions that represent statistical questions. What was the temperature at 5:0
Tju [1.3M]
I would answer but I’m in 6th grade and I don’t know how to
3 0
2 years ago
The school store marks up the price of all items by 30% before selling to
Readme [11.4K]

Answer:

$65.325 or $65.33

Step-by-step explanation:

When looking for a percentage in a number, you want to multiply that number by the percentage. Remember that all percentages are to the hundreth power, or 0.00. So if you want to find 30% of 50.25, you multiply it by 0.30 or 0.3. After calculating that you will come up with 15.075 as the percentage. Since the store is marking the price up, you add it to the original price. So your equation is 50.25 + 15.075 =?. After calculating that, you get the answer 65.325. That is only half of your answer though because, when dealing with money, you always round to the nearest hundredth. So when you round 65.325, you get 65.33 which should be the correct answer.

4 0
3 years ago
What is d and how would I find its value
denis23 [38]
D-value (meteorology) in meteorology refers to the deviation of actual altitude along a constant pressure surface from the standard atmosphere altitude of that surface.
3 0
3 years ago
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