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stiks02 [169]
3 years ago
10

This is what I need help with can someone please give me it it's a homework I don't get

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0
The answer looks like it's A.
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Lyrics to "nuketown" if you can put all the lyrics ill give you brainliest lol <3 ;)
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IT WONT LET ME PUT IT AFTER I LITERALLY BEEPED OUT EVERYTHING ISTG

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Alenkasestr [34]

All four choices are correct responses to the question.

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7x10 to the 3rd power, write a pattern to find the value of the expression
myrzilka [38]
Scientific notation is used to express very large or very small values.
Numbers in scientific notation are written in the form of  
m × 10 to the power of n
For example:
500 is written as 5 x 10^2 where:
500 = 5 x 10 x 10

Now, let's consider 7 x 10^3:
Following the same procedure:
7 x 10^3 = 7 x 10 x 10 x 10 = 7000
The pattern can be written as:
7 x 10^3 = 7 x 10 x 10^2 
              = 70 x 10^2
              = 70 x 10 x 10^1
              = 700 x 10
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6 0
3 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
Solve for a side in right triangles
natita [175]

Answer:

  2.30

Step-by-step explanation:

The side of interest is opposite the given angle, and the hypotenuse is given. The sine relation tells you ...

  sin(A) = a/c

  a = c·sin(A) = 3·sin(50°)

  a = BC ≈ 2.2981 ≈ 2.30

5 0
3 years ago
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