Ask question

Ask question

All categories

3 years ago

9

How do I solve these questions?

1 answer:

Lana71 [14]3 years ago

7 0

do you want all the questions answered?

You might be interested in

A manufacturer of cell phone batteries claims<br> That the average number

Misha Larkins [42]

I think you didn’t complete your que.stion. What are you asking ????0

8 0

3 years ago

Find all points on the x-axis that are 14 units from the point (4, -7).

BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

Distance between two points:

Suppose we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

$\sqrt{(x-4)^2+(0-(-7))^2} = 14$

$\sqrt{x^2 - 8x + 16 + 49} = 14$

$\sqrt{x^2 - 8x + 65} = 14$

$(\sqrt{x^2 - 8x + 65})^2 = 14^2$

$x^2 - 8x + 65 - 196 = 0$

$x^2 - 8x - 131 = 0$

So $a = 1, b = -8, c = -131$

$\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588$

$x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12$

$x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12$

The points are: (16.12,0),(-8.12,0).

4 0

3 years ago

+<br> 3. -5y- 10=-60<br> Solve the equation for -5y- 10=-60

In-s [12.5K]

Answer:

y=10

Step-by-step explanation:

you first add 10 to both sides

the bring down the -5y

thr divide it -50 with -5

6 0

4 years ago

What is 1.904 rounded to the nearest penny

solmaris [256]

Answer:

1.90 I believe this is the answer. Hope this helps! Have a great day!

6 0

3 years ago

Determine the mean, median, and more for the given data in each graph.

77julia77 [94]

5 is you median
4 is your mean

6 0

4 years ago