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Yuri [45]
3 years ago
10

Resolving power of a telescope whose objective lens has diameter 1.22m for a wavelength 4000 Å.​

Physics
1 answer:
Mamont248 [21]3 years ago
5 0

\sf \huge \purple{ Answer : - }

Diameter of objective lens = 1.22m

Wavelength of light = 4000Å

We have to find resolving power of telescope ..

★ Resolving power of telescope is given by

RP = D/1.22λ

  • D denotes diameter of lens
  • λ denotes wavelength of light

RP = D/1.22λ

RP = (1.22×10⁷)/(1.22×4)

RP = 0.25 × 10⁷

RP = 2.5 × 10⁶

★ Resolving power of microscope is given by

RP = 2μsinθ/λ

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