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FrozenT [24]
3 years ago
13

There is a species of starfish called the crown of thorns. This species is responsible for killing coral reefs around the world.

If you want to find out how these species have become so abundant around the world, who would you call? an astronomer a geologist a meteorologist an oceanographer Next Question Ask for help Turn it in
Physics
2 answers:
Elis [28]3 years ago
8 0

Answer:  oceanographer

An oceanographer is a special kind of scientist who studies various aspects of ocean such as marine ecology, chemistry of oceanic water, geology linked with ocean such as plate tectonics, earthquakes and volcanic eruptions, ocean water circulation and climatic influence of ocean on landmass. An oceanographer specialized in marine biology and ecology will study the interaction of marine animals and plants with each other and with the oceanic water.

Therefore, oceanographer is a scientist which can be called upon to study the interaction of species of starfish called as the crown of thorns with the coral reefs all around the world. The oceanographer can also find out the abundance of starfish species around the world.

zavuch27 [327]3 years ago
5 0
An oceanographer is the correct answer.
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Peter notices that his eight-year-old daughter frequently mentions the unusual habits of a new boy, who is from a different cult
pickupchik [31]
The answer should be C. Encourage his daughter to make friends with the new boy.

Hope this helps and have a happy new year
6 0
4 years ago
A ball has a mass of 2 kg and is thrown with a force of 8 Newtons for .35 seconds. What is the ball's change in
Anna [14]

Answer:

1.4s

Explanation:

Given parameters:

Mass of ball  = 2kg

Force  = 8N

Time  = 0.35s

Unknown:

Change in velocity  = ?

Solution:

To solve this problem, we use the expression obtained from Newton's second law of motion which is shown below:

      Ft  = m(v  - u)

 So;

         Ft  = m Δv

F is the force

t is the time

m is the mass

Δv is the change in velocity

             8 x 0.35  = 2 x Δv

                  Δv  = 1.4s

6 0
3 years ago
Mass (kg) 4.0
densk [106]

Answer:

25 m/s

Explanation:

First of all, we can find the acceleration the object by using Newton's second law of motion:

F=ma

where

F = 20.0 N is the net force applied on the object

m = 4.0 kg is the mass of the object

a is its acceleration

Solving for a, we find

a=\frac{F}{m}=\frac{20}{4}=5.0 m/s^2

Now we know that the motion of the object is a uniformly accelerated motion, so we can find its final velocity by using the following suvat equation:

v=u+at

where

v is the final velocity

u = 0 is the initial velocity

a=5.0 m/s^2 is the acceleration

t = 5 s is the time

By substituting,

v=0+(5.0)(5)=25 m/s

8 0
3 years ago
The light intensity incident on a metallic surface with a work function of 1.88 eV produces photoelectrons with a maximum kineti
ivanzaharov [21]

Answer:

KE = KE (incidental) - KE of emitted photons

or KE = h * f - Wf

So   h * f = KE + Wf = 1.2 + 1.88 = 3.08    incident energy

If you double the frequency then h * f = 6.16

KE = 6.16 - 1.2 = 4.96 eV

7 0
3 years ago
You are comparing two diffraction gratings using two different lasers: a green laser and a red laser. You do these two experimen
Nikolay [14]

Answer:

a. (a) grating A has more lines/mm; (b) the first maximum less than 1 meter away from the center

Explanation:

Let  n₁ and n₂ be no of lines per unit length  of grating A and B respectively.

λ₁ and λ₂ be wave lengths of green and red respectively , D be distance of screen and d₁ and d₂ be distance between two slits of grating A and B ,

Distance of first maxima for green light

= λ₁ D/ d₁

Distance of first maxima for red light

= λ₂ D/ d₂

Given that

λ₁ D/ d₁ = λ₂ D/ d₂

λ₁ / d₁ = λ₂ / d₂

λ₁ / λ₂  = d₁ / d₂

But

λ₁  <  λ₂

d₁ < d₂

Therefore no of lines per unit length of grating A will be more because

no of lines per unit length  ∝ 1 / d

If grating B is illuminated with green light first maxima will be at distance

λ₁ D/ d₂

As λ₁ < λ₂

λ₁ D/ d₂ < λ₂ D/ d₂

λ₁ D/ d₂ < 1 m

In this case position of first maxima will be less than 1 meter.

Option a is correct .

5 0
3 years ago
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