50 is tens and 150 is hundreds
The probability of having lunch together is p = 40% = 0.4
The probability of not having lunch together is q = 1 - p = 0.6
Number of trials (days in a week) is n = 7
Let r = number of days in the week when Andy and Anna have lunch together.
Use th graphing calculator to obtain
P(6 of 7) = ₇C₆ (0.4)⁶(0.6) = 0.017
P(7 of 7) = ₇C₇ (0.4)⁷(0.6)⁰ = 0.002
Therefore
P(at least 6 of 7) = P(1 of 7) + P(2 of 7) + ... + P(6 of 7)
= 0.131 + 0.261 + 0.290 + 0.194 + 0.077 + 0.017
= 0.97 or 97%
P(at least 6 of 7) = 0.017 + 0.002 = 0.019 = 1.9%
P(exactly 6 of 7) = 0.017 or 1.7%
Answer:
The probability of having lunch at least 6 days per week is 0.019 or 1.9%.
The probability of having lunch exactly 6 times is 0.017 or 1.7%
Answer:
80
Step-by-step explanation:
do 400÷5=80, as shown above
Answer:
Kindly check explanation
Step-by-step explanation:
Given the models for the median height of biys and giels:
BOY:
f(x) = 2.9√x + 20.1
GIRL:
f(x) = 3.1√x + 19
If x = 24 months
BOY:
HEIGHT = 2.9√24 + 20.1
= 2.9× 4.8989794 + 20.1
= 14.207040 + 20.1
= 34.307 inches
GIRL:
HEIGHT = 3.1√24 + 19
= 3.1 × 4.8989794 + 19
= 15.186836 + 19
= 34.1868 inches
If x = 48
Boy:
HEIGHT = 2.9√48 + 20.1
= 2.9× 6.9282032 + 20.1
= 20.091789 + 20.1
= 40.19 inches
Actual median height = 40.8
Hence, model underestimates by (40.80 - 40.19) = 0.61 inches
Girl:
HEIGHT = 3.1√48 + 19
= 3.1 × 6.9282032 + 19
= 21.477430 + 19
= 40.48 inches
Actual median height = 40.20
Hence, model overestimates by (40.48 - 40.20) = 0.28 inches
Well the total students are 25. The fraction is 12/25. So I think its that. Do you have any answer choices?