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amm1812
4 years ago
13

Please help! functions operations.

Mathematics
2 answers:
IgorC [24]4 years ago
4 0

Answer:

3

Step-by-step explanation:

Use the property:

f^{-1}(f(x))=x

This implies that;

f^{-1}(f(3))=3

The correct choice is the first option.

Or see it in details below:

Given

f(x)=9x+1

substitute x=3, to obtain;

f(3)=9(3)+1=28

Let y=9x+1

Interchange x and y.

x=9y+1

Solve for y.

x-1=9y

\frac{x-1}{9}=y

This implies that;

f^{-1}(x)=\frac{x-1}{9}

f^{-1}(f(3))=f^{-1}(28)

f^{-1}(28)=\frac{28-1}{9}

f^{-1}(28)=\frac{27}{9}=3

Zielflug [23.3K]4 years ago
3 0

The Answer is <u>A. 3. :D</u>

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A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc
aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0
4 years ago
Please please please help!!!
dalvyx [7]

9514 1404 393

Answer:

  2

Step-by-step explanation:

Fill in the argument value and look up the function value on the graph.

  (f\circ f)(-2) = f(f(-2)) = f(2) = \boxed{2}

7 0
2 years ago
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