AB = BC
3x-4=5x-10
-4=2x-10
6=2x
3=x
AB = 3x-4
AB = 3 (3)-4
AB = 9-4
AB =5
Therefore, AB is 5.
BC = 5x-10
BC = 5(3)-10
BC = 15-10
BC= 5
Let us first define Hypotenuse Leg (HL) congruence theorem:
<em>If the hypotenuse and one leg of a right angle are congruent to the hypotenuse and one leg of the another triangle, then the triangles are congruent.</em>
Given ACB and DFE are right triangles.
To prove ΔACB ≅ ΔDFE:
In ΔACB and ΔDFE,
AC ≅ DF (one side)
∠ACB ≅ ∠DFE (right angles)
AB ≅ DE (hypotenuse)
∴ ΔACB ≅ ΔDFE by HL theorem.
% is a number over 100, so 40% is 40/100, which is 0.40.
Answer:
the answer is c
Step-by-step explanation: