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4 years ago

10

7x^2/2x+6 divided by 3x-5/x+3

1 answer:

maks197457 [2]4 years ago

8 0

Answer:

$\large\boxed{\dfrac{7x^2}{6x-10}}$

Step-by-step explanation:

$\dfrac{7x^2}{2x+6}\div\dfrac{3x-5}{x+3}=\dfrac{7x^2}{2(x+3)}\cdot\dfrac{x+3}{3x-5}\\\\\text{cancel}\ (x+3)\\\\=\dfrac{7x^2}{2}\cdot\dfrac{1}{3x-5}=\dfrac{(7x^2)(1)}{(2)(3x-5)}\\\\\text{use the distributive property}\ a(b-c)=ab-ac\\\\=\dfrac{7x^2}{6x-10}$

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