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allochka39001 [22]
3 years ago
14

Rationalize the denominators: 4/√x+2

Mathematics
2 answers:
puteri [66]3 years ago
6 0
\dfrac{4}{\sqrt{x}+2}=\dfrac{4}{\sqrt{x}+2}\cdot\dfrac{\sqrt{x}-2}{\sqrt{x}-2}=\dfrac{4(\sqrt{x}-2)}{(\sqrt{x})^2-2^2}=\dfrac{4\sqrt{x}-8}{x-4}\\\\Use:(a+b)(a-b)=a^2-b^2
OLga [1]3 years ago
3 0
\frac{4}{\sqrt{x + 2}} = \frac{4}{\sqrt{x + 2}} * \frac{\sqrt{x + 2}}{\sqrt{x + 2}} = \frac{4\sqrt{x + 2}}{x + 2}
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By evaluating the given relation, we conclude that the correct options are A, D, and G.

<h3>How to check if the points are on the graph?</h3>

We have the relation:

k = ∛(V/7)

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So, to check if the points belong to the graph of the relation, we need to evaluate the points on the given relation and see if the relation is true.

A) (0, 0) gives:

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So we have the point (1, 0.52) and the point  (1, 1)  then does not belong to the graph.

We just need to do that for all the points, evaluate V and see if k gives the same value as in the point.

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If you want to learn more about evaluations, you can read:

brainly.com/question/4344214

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