Answer:
integers, rationals, irrational, real numbers, imaginary, and complex numbers.
A=Pe^(rt)
P = 800g
t = 8 years
A = 450g
r = This is what we will try and find to start with
450=800e^(r*8)
After running the math through a calculator, we end with r = -0.07192
Now we just re-input this information into our equation: A=800e^(-0.07192*16)
A=800e^(1.15072)
Now we will re-write the equation using the negative exponent rule:
A = 800 1/e^1.15072
Combine right side:
A = 800/e^1.15072
Then do the math:
A = 253.12709836......
That will give us A = 253 (rounded to the whole number)
I hope this helps! :)
Answer:
$6932
Step-by-step explanation:
Let last year's sales = x. Since there was a decrease of 5%, that means this year's sales are 95% of last year's sales.
So, .95x = 6585
x = 6932 to the nearest dollar
Select Is a Function or Is not a Function to correctly classify each relation.
<span><span>Title Is a Function Is not a Function</span><span><span><span><span>{<span><span>(<span>3, 7</span>)</span>,<span>(<span>3, 6</span>)</span>,<span>(<span>5, 4</span>)</span>,<span>(<span>4, 7</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>1, 5</span>)</span>,<span>(<span>3, 5</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>6, 4</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>2, 3</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>5, 8</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>0, 4</span>)</span>,<span>(<span>3, 2</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>6, 5</span>)</span></span>}</span></span>
</span></span></span>
Answer:
-9
Step-by-step explanation:
x² -16 = (x -4)(x +4)
This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).
... For x-4 = ±1, x = 3 or 5
... For x+4 = ±1, x = -3 or -5
The values of x that are ±3 both give |x²-16| = 7, a prime.
The values of x that are ±5 both give |x²-16| = 9, not a prime.
The two values of x that are of interest are x=-3 and x=3. Their product is ...
... (-3)·(3) = -9
