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3 years ago

Solve |P| > 3 A) {-3, 3} B) {P|-3 3}

Mathematics

1 answer:

Vesna [10]3 years ago

7 0

|P| > 3

P > 3 or - P > 3

P > 3 or P < - 3

Answer

C) {P| P < -3 or P > 3}

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I need answer please

zhenek [66]

Answer:

We know that lines l and m are parallel. The alternate interior angles rule states that the alternate interior angles formed by parallel lines are equal. So let's equate them.

2x + 22 = 4x

putting variables on one side,

22 = 4x - 2x

Thus 2x = 22

x becomes 22÷2

Therefore, x = 11.

pls give brainliest for the answer

8 0

3 years ago

If A (-3, 4) is one endpoint of a segment and B(-4,7) is the midpoint of the segment, find the other endpoint.

Nutka1998 [239]

Answer:

Take the slopes, such that 7-4/-4+3= 3/-1=-3

So one endpoijt is (-5,10)

8 0

3 years ago

At the movies, a couple bought 2 medium drinks and a large popcorn for $13.85. At the same theater, a family bought 3 medium dri

m_a_m_a [10]

Answer:

a) the cost of one medium drink be $3.80

b) the cost of a large popcorn be $6.25

Step-by-step explanation:

Let the cost of one medium drink be $x

and the cost of a large popcorn be $y

According to question,

A couple bought 2 medium drinks and a large popcorn for $13.85.

2x + y = 13.85 ..............(1)

A family bought 3 medium drinks and 2 large popcorn for a total of $23.90

3x + 2y = 23.90 ..............(2)

Using Elimination method to solve the system of equation,

Multiply equation (1) by 2 , we get,

4x + 2y = 27.70 ..............(3)

Now, subtract equation (2) from (3), we get,

4x + 2y-(3x + 2y) = 27.70 - 23.90

4x + 2y-3x - 2y = 3.80

4x -3x = 3.80

x = 3.80

Substitute, x = 3.8 in (1) ,

2(3.80) + y = 13.85

7.60 +y = 13.85

y = 6.25

Therefore, the cost of one medium drink be $3.80

and the cost of a large popcorn be $6.25

7 0

3 years ago

Read 2 more answers

Need help!

siniylev [52]

Correct Inputs :-

In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC

$\underline{\underline{\large\bf{Solution:-}}}\\$

$\longrightarrow$ Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.

$\leadsto$ Median is the line segment from a vertex to the midpoint of the opposite side.

Let us Check all options one by one

CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌

BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️

AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️

AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌

AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️

8 0

2 years ago

Express the area of square as monomial

V125BC [204]

A=x²
(where A is the area and x is the side length)

5 0

4 years ago

Solve |P| > 3 A) {-3, 3} B) {P|-3 < P < 3} C) {P|P < -3 or P > 3}