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2 years ago

Finn is swimming at a constant speed.

Mathematics

1 answer:

Reil [10]2 years ago

6 0

Answer:

31.25 seconds

Step-by-step explanation:

Examine division

11.6 + 24.4 = 36 m < 50m

and 36 + 37.2 - 73.2m > 50m

50 - 36 = 14m

14 * 23.25/37.2 = 8.75 seconds

7.25 + 15.25 + 8.75 = 31.25 seconds

so it would take him 31.25 seconds to swim 50 meters.

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Write the following expression in standard notation.

Liula [17]

It is the last one 21,400,000,000

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4 years ago

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90 POINTS PLEASE HELP

11111nata11111 [884]

$sin\alpha = - 0.8$

Step-by-step explanation:

We have , $cos\alpha = \frac{3}{5}$ , where $\alpha$ is located in IV quadrant! Let's find out value of $sin\alpha$ :

$sin\alpha = \sqrt{1-(cos\alpha )^2$

⇒ $sin\alpha = \sqrt{1-(cos\alpha )^2$

⇒ $sin\alpha = \sqrt{1-(\frac{3}{5} )^2$

⇒ $sin\alpha = \sqrt{1-(\frac{9}{25} )$

⇒ $sin\alpha = \sqrt{(\frac{25-9}{25} )$

⇒ $sin\alpha = \sqrt{(\frac{16}{25} )$

⇒ $sin\alpha = \pm {(\frac{4}{5} )$

Value of $sin\alpha$ is dependent on which quadrant it is . Since, in question it's given that $\alpha$ is located in IV quadrant , So $sin\alpha$ is negative i.e.

⇒ $sin\alpha = - {(\frac{4}{5} )$

⇒ $sin\alpha = - 0.8$

Therefore, $sin\alpha = - 0.8$ .

4 0

3 years ago

Read 2 more answers

The volume of a cube is 2197mm (cubed) what is the length of its side

Mademuasel [1]

Answer:

l^3=volume of cube

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3 years ago

An employee worked 36 hours last week. This week, she worked 15% less hours. How many hours did she work this week?

Lelu [443]

Answer: 30.6

Step-by-step explanation: she worked 30.6 hours be cause if you think 36 of 15% it is 30.6 hours she worked

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3 years ago

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

Vladimir [108]

Answer:

The value of t test statistics is 5.9028.

We conclude that the true mean is greater than 10 at the .01 level of significance.

Step-by-step explanation:

We are given that a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead.

The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.

Let $\mu$ = true mean transmission of pages.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 10 pages {means that the true mean is smaller than or equal to 10}

Alternate Hypothesis, $H_A$ : $\mu$ > 10 pages {means that the true mean is greater than 10}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 14.44 pages

s = sample standard deviation = 4.45 pages

n = sample of fax transmissions = 35

So, test statistics = $\frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$ ~ $t_3_4$

= 5.9028

(a) The value of t test statistics is 5.9028.

Now, at 0.01 significance level the z table gives critical values of 2.441 at 34 degree of freedom for right-tailed test.

Since our test statistics is more than the critical values of z as 5.9028 > 2.441, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean is greater than 10.

(b) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_3_4$ > 5.9028) = Less than 0.05% {using t table)

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3 years ago