Answer:
b. 144.8
Step-by-step explanation:
When calculating the moving average estimate of an observation , each of the observations are usually computed with the same weighted . In some cases, it is beneficial to assign different weight on the observations such that the observation closer to the time period being forecast, has higher weight. This is refer to as weighted moving average technique. The sum of the individual weight in a weighted moving average technique must equal to 1.
The three-period weighted moving average forecast for period 5 = 144*0.5 + 148 *0.3 + 142 *0.2 = 144.8
Answer:
7/16
Step-by-step explanation:
1. you have to have the same denominator
Answer:
Please check explanation
Step-by-step explanation:
Here, we want to do a matching.
We shall be matching the given statements with the features we have on the graph
Hence we shall be looking closely at the graph to answer the questions.
The y-intercept is the point at which the graph touches the y-axis
And it was at -3 degrees celsius at the beginning of the day.
The temperature was above zero between 8am and 8pm. The matching statement is that it is increasing or decreasing interval
We can see that the graph rose from 8am before it finally comes to zero at 8pm
Positive or negative interval matches with it was getting warmer between 2am and 2pm.
While temperature was lowest at 2am, we can see a peak at 2pm.
Answer:
290
Step-by-step explanation:
60% of ⅔X = 174
60/100 × 2/3 × X = 174
⅖X = 174
X = 435
⅔X = ⅔×435
290
290 cars are left in the parking,
145 cars left
The sum is 12x3+18x2-10x+8
