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Tems11 [23]
3 years ago
12

The graph shows the functions f(x), p(x), and g(x):

Mathematics
1 answer:
MakcuM [25]3 years ago
5 0
Part A:
The solution of p(x) and g(x) is the point of intersection of the two lines. Reading this off the diagram we can see that the point of intersection is (4, -3)

-----------------------------------------------------------------------------------------------------------------

Part B:
A solution for g(x) is any pair of coordinates that lie on the line g(x). We can choose any two coordinates; (5, -5) and (-6, 17)
--------------------------------------------------------------------------------------------------------------

Part C:
The solution to g(x) = f(x) is the point of intersection. From the graph, the point of intersection is (0, 5)


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Divide the sum of 8/7 and-3/14 by their difference
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Sum:

8/7+(-3/14)=13/14

difference:

8/7-(-3/14)=19/14

As per given condition we have,

sum/difference=(13/14)/(19/14)=13/19

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2 years ago
Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
amm1812

Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}

P(s_1|I)=\frac{0.015}{0.165}

P(s_1|I)=\frac{1}{11}

Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}

P(s_2|I)=\frac{0.12}{0.165}

P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}

P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

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That would be 644.8 / 31 = 20.8 feet / second
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X = velocity of plane
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2x = 756
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3 years ago
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