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3 years ago

PLEASE HELP!!!!!

Mathematics

1 answer:

sergey [27]3 years ago

8 0

D is the answer to your question

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5. If z=10 find the value of Z3-3(2-10)

avanturin [10]

Answer:

Step-by-step explanation:

BEDMAS

z=10

(10)3-3(2-10)

=(10)3-3(-8)

=30-(-24) *2 negatives = a positive

=30+24

=54

3 0

2 years ago

This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,

Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

Event A: Person has the flu.

Event B: Person got the flu shot.

The percentages associated with getting the flu are:

20% of 30%(got the shot).

65% of 70%(did not get the shot).

Hence:

$P(A) = 0.2(0.3) + 0.65(0.7) = 0.515$

The probability of both having the flu and getting the shot is:

$P(A \cap B) = 0.2(0.3) = 0.06$

Hence, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165$

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0

2 years ago

Which equation(s) have x = –3 as the solution? log3(2x + 15) = 2 log5(8x + 9) = 2 log4(–20x + 4) = 3 logx81 = 4

baherus [9]

Answer:

log_3(2x+15)=2 and log_4(-20x+4)=3

Step-by-step explanation:

Plug it in and see!

$log_3(2x+15)=2\\log_3(2(-3)+15)=2\\log_3(-6+15)=2\\log_3(9)=2\\\text{ This is a true equation because } 3^2=9\\\\\\log_5(8(-3)+9)=2\\log_5(-24+9)=2\\log_5(-15)=2\\\\\text{ Not true because you cannot do log of a negative number }\\\\log_4(-20(-3)+4)=3\\log_4(64)=3\\\text{ this is true because } 4^3=64\\\\\\log_x (81)=4\\log_{-3}(81)=4\\\text{ the base cannot be negative }\\\\\\\\\text{ There is only two options here} \\\\log_3(2x+15)=2 \text{ and } log_4(-20x+4)=3$