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Deffense [45]
3 years ago
7

What number is indicated on the number line

Mathematics
2 answers:
Burka [1]3 years ago
8 0
Mdnxndjddkdksjdndndkzzkxmxmdnf
g100num [7]3 years ago
3 0
Depends on the number line my guy
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Write a polynomial function with the given zeros x=-1,-1,6
damaskus [11]

Hello from MrBillDoesMath!

Answer:

x^3 - 6 x^2 - x + 6


Discussion:

The polynomial is

(x-1) (x - (-1)) (x-6) =

(x-1)(x+1)(x-6) =                     => as (x-1)(x+1) = x^2 - 1

(x^2-1)(x-6) =    

x^2(x) - 6 x^2 - 1x + 6 =

x^3 - 6 x^2 - x + 6



Thank you,

MrB

4 0
4 years ago
How do you solve this
Rainbow [258]

Answer: y+5 divided by 2

Step-by-step explanation:

add 5 to each side and then divide each side by 2

6 0
3 years ago
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PLEASE HURRY WILL MARK BRAINLIEST!!!
LekaFEV [45]

Answer:

-7y+8x

Step-by-step explanation:

-2y-x-5y+9x

3 0
3 years ago
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Riley makes a mistake in step 2 while doing her homework. What was her mistake? StartFraction x Over x squared minus 5 x + 6 End
kobusy [5.1K]

Answer:

The answer is:

She used the wrong common denominator

Step-by-step explanation:

Solving the given equation

\frac{x}{x^2-5x+6}+\frac{x}{x+3}\\\\Step 1: \frac{x}{(x-2)(x-3)}+\frac{x}{x+3}\\Step2: \frac{x}{(x-2)(x-3)}+\frac{x(x-2)}{(x-2)(x+3)}\\Step3:\frac{x(x+3)+x(x-2)(x+3)}{(x-2)(x-3)(x+3)}

Lets consider the steps given in the question:

Step2: \frac{x}{(x-2)(x+3)}+\frac{3(x-2)}{(x-2)(x+3)}

Step3: \frac{x+3(x-2)}{(x-2)(x+3)}\\

Lets compare both solutions:

In the original solution, the denominator of first term is (x-2)(x-3)

In the solution given in the question, the denominator of first term is (x-2)(x+3).

So the mistake she did in step 2 was that she change the sign of 3 in (x-3) from negative to positive, due to which she gets the wrong common denominator shown in Step 3.

7 0
4 years ago
Read 2 more answers
A long distance phone company charges a $2.95 monthly fee plus $0.14 for each minute write an algebraic expression to show the c
nataly862011 [7]

Answer:

2.95+0.14t=x

i think but ehhh, i am pretty sure about the constant but not to sure about the varibles

7 0
3 years ago
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