Okay I'm not sure which you need help with but.
First one, it means how did you feel about how the worksheets were set up
Then, about what you learned
How you felt about tests
And for the last one you could say thing like
How you felt about obstacles, the teachers/professors, pressure, how much you think you learned, how you feel at the end of the school year versus the beginning, or how you grew as a student/person. You can pick one or two or your own, those are just some ideas.
How is this your last day at school? You are quite lucky
Answer:
x = 8 and y = 10
Step-by-step explanation:
Since the figures are congruent:
Angle PQR = EFG
6y + x = 68
Segment QR = FG
2x - 4 = 12
Solving that:
2x - 4 = 12
2x = 16
x = 8
Replacing x in 6y + x =68
6y + 8 = 68
6y = 60
y = 10
Using Pythagoras theorem
|AB|*2=|d/2|=(5*2)+12*2
AB*2=25+144
AB=13
D/2= r=6.5cm
tan¥=6.5/5
tan¥=1.3
¥=tan inverse of (1.3)
¥=52.43 degrees
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
Answer:
Slope = -1
Step-by-step explanation:
6-5/3-4=-1
(can I get brainliest please)
