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Virty [35]
3 years ago
10

∠5 is a supplement of ∠6, and m∠5=78°. Find m∠6.

Mathematics
1 answer:
vekshin13 years ago
6 0

Answer:

102^\circ

Step-by-step explanation:

Given that:

\angle 5 is a supplement of \angle 6.

m\angle 5 = 78°

To find:

m\angle 6 = ?

Solution:

First of all, let us learn about the concept of an angle being a supplement of the other angle.

\angle B is known as supplement of \angle A, if sum of the two angles is equal to 180°.

i.e. \angle A +\angle B=180^\circ.

For example, angle made on one side by a line intersecting the other line are supplement of each other.

Here, we are given that \angle 5 is a supplement of \angle 6.

In other words:

\angle 5+\angle 6=180^\circ

Putting value of \angle 5:

\Rightarrow 78^\circ+\angle 6=180^\circ\\\Rightarrow \angle 6 =180^\circ-78^\circ\\\Rightarrow \bold{\angle 6 =102^\circ\\}

So, the answer is: 102^\circ

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2 years ago
8. In the figure, ADC is a straight line.
dlinn [17]

Answer:

a). ΔABC ~ ΔBDC

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Step-by-step explanation:

If ΔABC ~ ΔBDC,

a). Ratio of the corresponding sides of both the triangles will be equal.

\frac{AB}{BD}=\frac{BC}{DC}=\frac{AC}{BC}

\frac{BC}{DC}=\frac{AC}{BC}

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Since Ratio of the corresponding sides are same, therefore, both the triangles are similar.

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Read 2 more answers
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected cont
DiKsa [7]
 Given that a display allows a customer to hook together any selection of components, one of each type. These are the types:
Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood
CD player: Onkyo, Pioneer, Sony, Technics
Speakers: Boston, Infinity, Polk
Cassette: Onkyo, Sony, Teac, Technics:

Part (a):
In how many ways can one component of each type be selected?

The number of ways one type of receiver will be selected is given by 5C1 = 5
The number of ways one type of CD player will be selected is given by 4C1 = 4
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways one component of each type can be selected is given by 5 x 4 x 3 x 4 = 240 ways



Part (b):
In how many ways can components be selected if both the receiver and the compact disc player are to be Sony?

The number of ways of selecting a Sony receiver is 1
The number of ways of selecting a Sony CD player is 1
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways components can be selected if both the receiver and the compact disc player are to be Sony is given by 1 x 1 x 3 x 4 = 12



Part (c)
In how many ways can components be selected if none of them are Sony?

The number of ways one type of receiver that is not Sony will be selected is given by 4C1 = 4
The number of ways one type of CD player that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of speakers that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of cassette that is not Sony will be selected is given by 3C1 = 3

Therefore, the number of ways that components can be selected if none of them are Sony is given by 4 x 3 x 3 x 3 = 108



Part (d):
In how many ways can a selection be made if at least one Sony component is to be included?

The total number of ways of selecting one component of each type is 240
The number of ways that components can be selected if none of them are Sony is 108

Therefore, the number of ways of selecting at least one Sony component is given by 240 - 108 = 132



Part (e):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains at least one Sony component?

The total number of ways of selecting one component of each type is 240
The number of ways of selecting at least one Sony component is 132

Therefore, the probability that a system selected at random contains at least one Sony component is given by 132 / 240 = 0.55



Part (f):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains exactly one Sony component? (Round your answer to three decimal places.)

The number of ways of selecting only a Sony receiver is given by 1 x 3 x 3 x 3 = 27
The number of ways of selecting only a Sony CD player is given by 4 x 1 x 3 x 3 = 36
The number of ways of selecting only a Sony cassette is given by 4 x 3 x 3 x 1 = 36

Thus, the number of ways of selecting exactly one Sony component is given by 27 + 36 + 36 = 99

Therefore, the probability that a system selected at random contains exactly one Sony component is given by 99 / 240 = 0.413
5 0
3 years ago
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