1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Firlakuza [10]
2 years ago
6

HELP

Mathematics
2 answers:
ladessa [460]2 years ago
7 0
Use the Pythagorean Theorem:
 A²+B²=C²
 6²+5²=C²
36+25=C²
       61=C²
    √61=C
So the answer is C.

Sindrei [870]2 years ago
7 0

Answer:

Correct answer is option C (√61)

Step-by-step explanation:

in this question we have given a right triangle in which

∠C=90^{0}

BC = 6 and AC = 5

we have to find the length of the hypotenuse, AB=?

To find the the hypotenuse we will apply Pythagoras theorem (According to Pythagoras theorem, "in a right angle triangle, square of hypotenuse is equal to the sum of square of other two sides")

In ΔABC by Pythagoras theorem

AB^{2}=AC^{2}+BC^{2}...................(1)

put values of BC and AC in equation 1

AB^{2}=5^{2}+6^{2}

AB^{2}=25+36

AB^{2}=61

AB=√61

You might be interested in
160,000,000 in scientific notation and 58,413,000,000 please help me guys!!!
elixir [45]

160000000 =

move the decimal so only one number is to the left

we need to move it 8 times

1.60000000 *10^8

1.6*10^8

58413000000

move the decimal so only one number is to the left

5.8413000000 * 10^10

5.8413*10^10

3 0
3 years ago
√131 is between 11 and 12? true or false
guajiro [1.7K]
True
11 is √121
12 is √144
So √131 is in between 11 and 12
6 0
2 years ago
Read 2 more answers
PLEASE Help on the following questions. (8th Grade Math) {40 points!} No need for the explanations just the answers.
anastassius [24]

Answer:

Im sorry. give me a few minutes and I will get you a few of the answers. I will comment on your questions with the answers I get. No promises that they will be right because I am also in 8th grade.

Step-by-step explanation:

8 0
2 years ago
A triangle has vertices T(-2,4), E(6,2), and D(1,-1). Is ATED a right triangle?
inessss [21]

Answer:

  • B. Yes, because ED is perpendicular to DT which makes a right angle.

Step-by-step explanation:

Plot the given points and connect in pairs to get a triangle.

Visually we can say it is a right triangle as legs TD and ED seem perpendicular.

Let's confirm this by finding the slopes.

<u>Slope of TD:</u>

  • m = (-1 - 4)/(1 -(-2)) = -5/3

<u>Slope of ED:</u>

  • (-1 - 2)/ (1 - 6) = -3/-5 = 3/5

<u>Product of the slopes is:</u>

  • -5/3*3/5 = -1

This confirms DT⊥ED

Correct choice is B

6 0
2 years ago
The price was
ryzh [129]

Answer: $165

Step-by-step explanation: Divide the new price by 1, + the percent of increase. 198 / 1.20 = 165

<u><em>MARK AS BRAINLIEST PLEASE! ;D</em></u>

8 0
2 years ago
Other questions:
  • HELP !! I NEED SOMEONE TO DO THIS TO ME!!
    12·1 answer
  • The circumference of a circle is 16π cm. What is the area, in square centimeters? Express your answer in terms of \piπ.
    9·2 answers
  • A train travels 3.5 kilometers on a straight track with grade of 1 degree 10'. What is the vertical rise of the train distance?
    9·1 answer
  • Why you would make one of the addends a tens number when solving an additional problem
    8·2 answers
  • For each line, state its slope and its y-intercept. 6y-2x=15
    15·1 answer
  • What is the domain and range of (-6,3), (-1,2), (0,3), (2,4), (5, -1)
    11·2 answers
  • Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif
    12·1 answer
  • Which algebraic expression represents “Marcus ran four times as far this week”? 4 + n 4n n – 4
    15·2 answers
  • Given that the base of the rock is 14 feet, and the height of the rock is 12 feet, what is the slope on which the vehicle is lea
    13·2 answers
  • For a school fundraiser Paul bought a big box of ducks and wrote prize amounts, in dollars on the bottom of each rubber duck. Th
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!