Answer:
![[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]](https://tex.z-dn.net/?f=%5Bp-%7Cp%7C%2A10%5E%7B-3%7D%20%5C%2C%20%2C%20%5C%2C%20p%2B%7Cp%7C%2A%2010%5E-3%5D)
Step-by-step explanation
The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is
r = |p*-p|/|p|
we want r to be at most 10⁻³, thus
|p*-p|/|p| ≤ 10⁻³
|p*-p| ≤ |p|* 10⁻³
therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]
Answer:
A.) The coordinates of M' are (-2/4, -4/5)
The coordinates of N' are (1/5, 1)
B.) The scale factor of the dialation is 3
Answer:
153.86
Step-by-step explanation:
3.14(7)^2
3.14 × (7 × 7)
3.14 × 49
153.86
We have that
Profit margin is calculated by finding the net profit as a percentage of the revenue
Profit margin = [Net profit / Revenue]
Net profit= [Revenue-Cost]
we know that
Revenue = $16.25 million
Cost = $13.5 million + $2.7 million
Net profit = [16.25 million - (13.5 million + 2.7 million)]
Net profit = $0.05 million
Profit margin = 0.05 / 16.25
Profit margin = 0.003077 or 0.3077%
