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Lerok [7]
3 years ago
15

A certain make of car is available in 5 body types, 4 colors, and 3 kinds of upholstery. How many cars would a dealer have to ke

ep in stock to be able to show his complete line to prospective customers?
Mathematics
2 answers:
NeX [460]3 years ago
7 0
So there's 5 body types each with 4 colors. 5x4 is 20. For each of these 20 cars there is 3 kinds of upholstery. 20x3 is 60. Therefore, the dealer would need a minimum of 60 cars to show his complete line. Hope this helped!
makkiz [27]3 years ago
6 0

Answer:

60 cars

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
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vovikov84 [41]

Answer:

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Step-by-step explanation:

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5 0
4 years ago
If u multiply 2/3 x 6/10, will the product be more than 6/10 or less than 6/10? How do you know?
Elanso [62]

Answer:

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Step-by-step explanation:

You can find a common denominator and get 20/30 * 18/30 = 38/30, which is more than 18/30.

5 0
3 years ago
PLEASE HELP SOON Find the value of x. Round to the nearest tenth. 27° х 34° 11 X = ? [?] 9 Law of Sines: sin A sin C sin B b a E
Tatiana [17]

The picture of the problem has been attached below :

Answer:

13.5

Step-by-step explanation:

Applying the sine rule to solve for x

SinA /a = SinB / b = SinC/ c

Sin 34 / x = Sin 27/11

Cross multiply :

11 * sin34 = x * sin 27

6.1511219 = 0.4539904x

Divide both sides by 0.4539904

6.1511219/0.4539904 = x

13.549 = x

x = 13.5

5 0
3 years ago
Who had the correct answer?
Amiraneli [1.4K]

Check the picture below.

8 0
3 years ago
Read 2 more answers
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