Question

Which equation is the inverse of 2(x-2)squared=8(7+y)

Answer 1

Answer:

$f^{-1}(x)=2(+/-)2\sqrt{(7+x)}$

Step-by-step explanation:

we have

$2(x-2)^{2}=8(7+y)$

step 1

Exchange x for y and y for x

$2(y-2)^{2}=8(7+x)$

step 2

isolate the variable y

$(y-2)^{2}=4(7+x)$

take the square root both sides

$y-2=(+/-)\sqrt{4(7+x)}$

$y=2(+/-)\sqrt{4(7+x)}$

step 3

Let

$f^{-1}(x)=y$

$f^{-1}(x)=2(+/-)\sqrt{4(7+x)}$

$f^{-1}(x)=2(+/-)2\sqrt{(7+x)}$  ----> equation of the inverse