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3 years ago

What is the pattern between 1/4, 1/2, 3/4, and 1

Mathematics

1 answer:

bagirrra123 [75]3 years ago

4 0

Answer:

Adding 1/4 each time

Step-by-step explanation:

1/4+1/4=1/2

1/2+1/4=3/4

3/4+1/4=1

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Solve the system of linear equations by substitution. 2x-y=3 x+5y=14

adoni [48]

Let 2x – y = 3 ——— equation 1

Let x + 5y = 14 ——— equation 2

Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3

• Put eqn 3 in eqn 2

(y + 3 / 2) + 5y = 14

6y = 14 – 3/2

6y = 25/2

y = 25/12

• put y = 25/12 in eqn 3

x = (25/12 + 3/2)

x = 43/12

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3 years ago

Help pls!!!!!!!!!!!!!!!!!

const2013 [10]

Answer: just turn them into decimals and use a calculator then turn them back into fractions in simplified form

Step-by-step explanation:

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2 years ago

Sales Tax selling price $70.00 rate of sales tax 3% sales tax (?)

goldfiish [28.3K]

Answer:

$2.10

Step-by-step explanation:

change the rate of sales tax to a decimal by dividing by 100, so 3%=.03

multiply the price by .03

4 0

2 years ago

Read 2 more answers

Plz I need some help with 11-12 . My teacher didn’t even explain it correctly so now I’m confused.

rusak2 [61]

Answer:

Step 1: Transpose everything to one side

12. x²+16x+15-10x+4=0

Step 2: Add the like terms

x² + (16x - 10x) + 15 + 4=0

x² + 6x + 19=0

Step 3: Use the quadratic formula to get the value(s) of x.

a=1 b=6 c=19

$x = \frac{ - b + - \sqrt{b {}^{2} - 4ac } {}^{} }{2a}$

therefore, x=... or x

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2 years ago

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0

1 year ago